Chapter 0.11, Problem 6E

To determine

The probability of finding a coin at most 1 dollars from the jar.

Answer to Problem 6E

  $P=1$

Explanation of Solution

Given:

Nickel coin = 70

Dim coin = 100

Quarter coin = 80

One-dollar coin = 50

Formula used:

Probability (P) = $\frac{\text{Possible event}\left(PE\right)}{\text{Total event}\left(TE\right)}$

Calculation:

Total number of coins,

  $\begin{array}{l}TE=70+100+80+50\\ TE=300\end{array}$

1 Nickel coin = 0.05 dollars

1 Dime coin = 0.1 dollars

1 Quarter coin = 0.25 dollars

Total coins which are less than 0.1 dollars,

  $\begin{array}{l}PE=70+100+80+50\\ PE=300\end{array}$

By the probability formula,

  $\begin{array}{l}P=\frac{PE}{TE}\\ P=\frac{300}{300}\\ P=1\end{array}$

Conclusion:

Hence, the probability of finding a coin at most 1 dollars from the jar is 1.