Chapter 0, Problem 62POT

To determine

To find: the probability of not getting blue marble in the given conditions.

Answer to Problem 62POT

  $P\left(\text{not blue}\right)=\frac{3}{5}$ .

Explanation of Solution

Given:

The given condition is:

One marble is randomly selected from 3 red, 4 green, 2 black, and 6 blue marbles.

Concept used:

Probability of the events is given by

  $P\left(E\right)=\frac{\text{Number of possible outcomes}}{\text{Total number of possible outcomes}}$

Calculation:

According to the question, total number of outcomes is $3+4+2+6=15\text{marbles}$ .

number of blackmarbles is 2 bluemarbles.

Therefore, the probability of blueis $P\left(\text{blue}\right)=\frac{6}{\text{15}}$

Therefore, probability of not getting blue marble is

  $\begin{array}{l}P\left(\text{not blue}\right)=1-P\left(\text{blue}\right)\\ =1-\frac{6}{\text{15}}=\frac{9}{15}=\frac{3}{5}\end{array}$

Hence, the probability of not getting blue marble is $P\left(\text{not blue}\right)=\frac{3}{5}$ .