Chapter 0.11, Problem 1E

To determine

The probability of the given data.

Answer to Problem 1E

  $\mathrm{P}\left(nickel\right)=\frac{70}{300}=\frac{7}{30}$

Explanation of Solution

Given :

  $\begin{array}{l}nickel=70\\ \dim es=100\\ quarters=80\\ One-dollarcoin=50\end{array}$

Solution:

  $\begin{array}{l}totaloutcome=70+100+80+50\\ totaloutcome=300\end{array}$

Probability:

  $\mathrm{Pr}obability=\frac{probableoutcome}{totaloutcome}$

  $\begin{array}{l}totaloutcome=70+100+80+50\\ totaloutcome=300\\ \mathrm{P}\left(nickel\right)=\frac{70}{300}=\frac{7}{30}\\ P\left(\text{dime}\right)=\frac{100}{300}=\frac{1}{3}\\ P\left(quarter\right)=\frac{80}{300}=\frac{4}{15}\\ P\left(one-dollarbill\right)=\frac{50}{300}=\frac{1}{6}\end{array}$