Chapter 0, Problem 20PRT

To determine

To calculate: The fraction of boys in the Mrs. Hudson’s class with the fraction of girls as $\frac{3}{5}$ .

Answer to Problem 20PRT

The fraction of boys in the Mrs. Hudson’s class is $\frac{2}{5}$ .

Explanation of Solution

Given information:

It is given that fraction of girls in Mrs. Hudson’s class is $\frac{3}{5}$ .

Formula used:

The difference of two or more terms is denoted by $-$ sign that is if two terms are separated by $-$ then they are subtracted from one term to the other.

Calculation:

Consider that fraction of girls in Mrs. Hudson’s class is $\frac{3}{5}$ . As, there are only boys and girls in the class and total fraction is always 1. So, fraction of boys is,

  $\frac{1}{1}-\frac{3}{5}$

Observe that the denominator is not same in both the rational numbers, so take the lowest common multiple of denominators 1 and 5 as 5.

  $\begin{array}{c}\frac{1}{1}-\frac{3}{5}=\frac{\left(1\times 5\right)-\left(3\times 1\right)}{5}\\ =\frac{5-3}{5}\\ =\frac{2}{5}\end{array}$

The above expression cannot be simplified further.

Therefore, the fraction of boys in the Mrs. Hudson’s class is $\frac{2}{5}$ .