You take 10.00 grams of pure acetic acid add top it up to 1.00 liter of solution

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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  • You take 10.00 grams of pure acetic acid add top it up to 1.00 liter of solution.
    1. What is the pH of the solution at equilibrium? You will need to look up the pKa or Ka of acetic acid to figure this out (just google it).
    2. You add 20.00 grams of sodium acetate to the mixture and it causes a negligible increase in volume. What is the new pH once the solution reaches equilibrium?
    3. You add 1.00 mole of HClO4 (a strong acid) causing a negligible increase in volume again. What is the new pH?
    4. You add 1.00 mole of NaOH (strong base) causing a negligible increase in volume AGAIN (somehow?). What is the new pH?
Expert Solution
Step 1

 Note: Since we only answer upto 3 sub parts we will answer the first 3.Please resubmit the question and specify the other sub parts.

 

Given data:

  1.  pH of the solution at equilibrium need to calculate. 
  2. If  20.00 grams of sodium acetate is added to the mixture and it causes a negligible increase in volume.  Then new pH whenthe solution reaches equilibrium need to calculate.
  3. When 1.00 mole of HClO4 is added a negligible increase in volume again.  New pH need to be write.

 

 

 

 

Step 2
  • 10.00 grams of pure acetic acid added to make 1.00 liter of solution.
  • Amount of CH3COOH =10 gm
  • Molecular weight of CH3COOH = 60.052 gm.
  • Ka of acetic acid=1.8 x 10 -5
  • Moles of CH3COOH =10.00/60.052  moles =0.167 moles.
  • Molarity of CH3COOH =0.167 mole/1 litre =0.167 M

Chemistry homework question answer, step 2, image 1

 The dissociation of acetic acid is given by the equation:

Chemistry homework question answer, step 2, image 2

From ICE table

table

CH3COOH

CH3COO-

H3O+

I

0.167 M 0 0
C -x +x +x
E 0.167-x +x +x

 

 

Step 3

 

 

Chemistry homework question answer, step 3, image 1

Thus the pH of the solution of equilibrium is 2.76.

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