Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Use each expression for the equilibrium constant to write a chemical equation.
![**Equilibrium Constants in Chemical Reactions**
**a.** \( K = \frac{[A_2]}{[A]^2} \)
This formula represents the equilibrium constant expression for a reaction where two moles of element or compound \( A \) form a molecule \( A_2 \). The concentration of the product \( A_2 \) is divided by the square of the concentration of the reactant \( A \).
**b.** \( K = \frac{[AB_3]^2}{[A_2][B_2]^3} \)
This expression is used for a reaction where two moles of compound \( AB_3 \) are formed from single moles of molecules \( A_2 \) and three moles of \( B_2 \). The square of the concentration of \( AB_3 \) is divided by the product of the concentrations of \( A_2 \) and the cube of \( B_2 \).
The calculations for \( K \) (equilibrium constant) allow us to understand the ratio of the concentrations of products to reactants at equilibrium, providing insight into the reaction's favorability.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ecf5b80-2518-4246-9cf0-28fbc9ab655e%2F0fbd9603-4cd7-48f8-a693-aed8aedab97e%2Fxfa52c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Equilibrium Constants in Chemical Reactions**
**a.** \( K = \frac{[A_2]}{[A]^2} \)
This formula represents the equilibrium constant expression for a reaction where two moles of element or compound \( A \) form a molecule \( A_2 \). The concentration of the product \( A_2 \) is divided by the square of the concentration of the reactant \( A \).
**b.** \( K = \frac{[AB_3]^2}{[A_2][B_2]^3} \)
This expression is used for a reaction where two moles of compound \( AB_3 \) are formed from single moles of molecules \( A_2 \) and three moles of \( B_2 \). The square of the concentration of \( AB_3 \) is divided by the product of the concentrations of \( A_2 \) and the cube of \( B_2 \).
The calculations for \( K \) (equilibrium constant) allow us to understand the ratio of the concentrations of products to reactants at equilibrium, providing insight into the reaction's favorability.
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