Hydrofluoric acid is important in both pharmaceutical synthesis and the synthesis of Teflon. It can be produced by reacting H2 with F2, H2(g) + F2(g)-> 2 HF(g). If you ran = 2.00M, what would the the reaction with initial concentrations of H2 and F2 concentration of HF be at equilibrium? The Kc =115. Oa. 3.37 M Ob. 0.85 M Oc. 1.69 M Od. 4.00 M e. 2.85 M
Hydrofluoric acid is important in both pharmaceutical synthesis and the synthesis of Teflon. It can be produced by reacting H2 with F2, H2(g) + F2(g)-> 2 HF(g). If you ran = 2.00M, what would the the reaction with initial concentrations of H2 and F2 concentration of HF be at equilibrium? The Kc =115. Oa. 3.37 M Ob. 0.85 M Oc. 1.69 M Od. 4.00 M e. 2.85 M
Chemistry
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Chapter1: Chemical Foundations
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![### Hydrofluoric Acid Synthesis
Hydrofluoric acid is important in both pharmaceutical synthesis and the synthesis of Teflon. It can be produced by reacting hydrogen gas (H₂) with fluorine gas (F₂) as follows:
\[ \text{H}_2(g) + \text{F}_2(g) \rightarrow 2 \text{HF}(g) \]
If you ran the reaction with initial concentrations of \(\text{H}_2\) and \(\text{F}_2 = 2.00 \, \text{M}\), what would the concentration of HF be at equilibrium? The equilibrium constant (\(K_c\)) is 115.
**Options:**
- a. 3.37 M
- b. 0.85 M
- c. 1.69 M
- d. 4.00 M
- e. 2.85 M
In this question, you are required to determine the concentration of hydrofluoric acid (HF) at equilibrium given the initial concentrations of the reactants and the equilibrium constant.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07e9effc-21af-434f-b1d9-5938ea63da08%2Fb420dc25-653f-4b61-a2fe-5aba51a6f3d9%2Fg8etkct_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Hydrofluoric Acid Synthesis
Hydrofluoric acid is important in both pharmaceutical synthesis and the synthesis of Teflon. It can be produced by reacting hydrogen gas (H₂) with fluorine gas (F₂) as follows:
\[ \text{H}_2(g) + \text{F}_2(g) \rightarrow 2 \text{HF}(g) \]
If you ran the reaction with initial concentrations of \(\text{H}_2\) and \(\text{F}_2 = 2.00 \, \text{M}\), what would the concentration of HF be at equilibrium? The equilibrium constant (\(K_c\)) is 115.
**Options:**
- a. 3.37 M
- b. 0.85 M
- c. 1.69 M
- d. 4.00 M
- e. 2.85 M
In this question, you are required to determine the concentration of hydrofluoric acid (HF) at equilibrium given the initial concentrations of the reactants and the equilibrium constant.
Expert Solution
Step 1
The reaction taking place is given as,
=> H2 (g) + F2 (g) --------> 2 HF (g) Kc = 115
Given : Initial concentration of F2 = 2.00 M
And Initial concentration of H2 = 2.00 M
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