) ListenThe Kep value for calcium sulfate [CaSO4) is 2.40 X 10-5 and a professor made 1825mL of a CaSO4lag) solution but then one of his graduate student accidentally pouredin a 0.125 M solution of calcium phosphate [Ca3(PO4)2] solution. You may ignorethe additional volume coming from the Cag(PO4)2 solution to make the calculationsimpler. Calculate the new equilibrium constant (K) with this common ion effect.1.20 x 10-53.44 x 10-53.84 x 10-52.01 x 10-5O 1.48 x 10-51591....docxLAB EXP, #3 -.docxShow All

Given: Ksp of CaSO4 = 2.4010-5 Volume of CaSO4 = 1825 mL Concentration of Ca3(PO4)2 = 0.125 M

The Ksp value for calcium sulfate [CaSO4] is 2.40 X 105 and a professor made 1825 mL of a CaSO4(ag) solution but then one of his graduate student accidentally poured in a 0.125 M solution of calcium phosphate [Ca3(P04)2] solution. You may ignore the additional volume coming from the Ca3(PO4)2 solution to make the calculation simpler. Calculate the new equilibrium constant (K) with this common ion effect.

The Ksp value for calcium sulfate [CaSO4] is 2.40 X 105 and a professor made 1825 mL of a CaSO4(ag) solution but then one of his graduate student accidentally poured in a 0.125 M solution of calcium phosphate [Ca3(P04)2] solution. You may ignore the additional volume coming from the Ca3(PO4)2 solution to make the calculation simpler. Calculate the new equilibrium constant (K) with this common ion effect.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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