A student ran the following reaction in the laboratory at 656 K: 2NH3 (9) N₂(g) + 3H₂(g) When she introduced 0.0783 moles of NH3(g) into a 1.00 liter container, she found the equilibrium concentration of H₂(g) to be 0.108 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = this question.

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**Transcription:**

A student ran the following reaction in the laboratory at 656 K:

\[ 2\text{NH}_3 (g) \rightleftharpoons \text{N}_2 (g) + 3\text{H}_2 (g) \]

When she introduced 0.0783 moles of \(\text{NH}_3 (g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{H}_2 (g)\) to be 0.108 M.

Calculate the equilibrium constant, \( K_c \), she obtained for this reaction.

\[ K_c = \]
Transcribed Image Text:**Transcription:** A student ran the following reaction in the laboratory at 656 K: \[ 2\text{NH}_3 (g) \rightleftharpoons \text{N}_2 (g) + 3\text{H}_2 (g) \] When she introduced 0.0783 moles of \(\text{NH}_3 (g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{H}_2 (g)\) to be 0.108 M. Calculate the equilibrium constant, \( K_c \), she obtained for this reaction. \[ K_c = \]
Expert Solution
Step 1

Ammonia decomposes into nitrogen and hydrogen. The equation for the balanced chemical reaction is as follows:

2NH3(g)  ⇌  N2(g) +  3H2(g)

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