A student ran the following reaction in the laboratory at 531 K:\[ \text{PCl}_3 (g) + \text{Cl}_2 (g) \rightleftharpoons \text{PCl}_5 (g) \]When she introduced 0.0811 moles of \(\text{PCl}_3 (g)\) and 0.115 moles of \(\text{Cl}_2 (g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{Cl}_2 (g)\) to be 0.0646 M.Calculate the equilibrium constant, \(K_c\), she obtained for this reaction.\[ K_c = \boxed{\phantom{K}} \] A student ran the following reaction in the laboratory at 427 K:\[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \]When she introduced 3.96 moles of \(\text{PCl}_5(g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{Cl}_2(g)\) to be 0.0387 M.Calculate the equilibrium constant, \(K_c\), she obtained for this reaction.\[ K_c = \]

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Answered: Tabo PC13 (g) + Cl₂ (g) ⇒ PC15 (9) she…

Tabo PC13 (g) + Cl₂ (g) ⇒ PC15 (9) she introduced 0.0811 moles of PC13 (9) and d the equilibrium concentration of Cl₂ (g) to be late the equilibrium constant, Kc, she obtained

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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