Tabo PC13 (g) + Cl₂ (g) ⇒ PC15 (9) she introduced 0.0811 moles of PC13 (9) and d the equilibrium concentration of Cl₂ (g) to be late the equilibrium constant, Kc, she obtained

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A student ran the following reaction in the laboratory at 531 K:

\[ \text{PCl}_3 (g) + \text{Cl}_2 (g) \rightleftharpoons \text{PCl}_5 (g) \]

When she introduced 0.0811 moles of \(\text{PCl}_3 (g)\) and 0.115 moles of \(\text{Cl}_2 (g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{Cl}_2 (g)\) to be 0.0646 M.

Calculate the equilibrium constant, \(K_c\), she obtained for this reaction.

\[ K_c = \boxed{\phantom{K}} \]
Transcribed Image Text:A student ran the following reaction in the laboratory at 531 K: \[ \text{PCl}_3 (g) + \text{Cl}_2 (g) \rightleftharpoons \text{PCl}_5 (g) \] When she introduced 0.0811 moles of \(\text{PCl}_3 (g)\) and 0.115 moles of \(\text{Cl}_2 (g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{Cl}_2 (g)\) to be 0.0646 M. Calculate the equilibrium constant, \(K_c\), she obtained for this reaction. \[ K_c = \boxed{\phantom{K}} \]
A student ran the following reaction in the laboratory at 427 K:

\[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \]

When she introduced 3.96 moles of \(\text{PCl}_5(g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{Cl}_2(g)\) to be 0.0387 M.

Calculate the equilibrium constant, \(K_c\), she obtained for this reaction.

\[ K_c = \]
Transcribed Image Text:A student ran the following reaction in the laboratory at 427 K: \[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \] When she introduced 3.96 moles of \(\text{PCl}_5(g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{Cl}_2(g)\) to be 0.0387 M. Calculate the equilibrium constant, \(K_c\), she obtained for this reaction. \[ K_c = \]
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