Tabo PC13 (g) + Cl₂ (g) ⇒ PC15 (9) she introduced 0.0811 moles of PC13 (9) and d the equilibrium concentration of Cl₂ (g) to be late the equilibrium constant, Kc, she obtained
Tabo PC13 (g) + Cl₂ (g) ⇒ PC15 (9) she introduced 0.0811 moles of PC13 (9) and d the equilibrium concentration of Cl₂ (g) to be late the equilibrium constant, Kc, she obtained
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A student ran the following reaction in the laboratory at 531 K:
\[ \text{PCl}_3 (g) + \text{Cl}_2 (g) \rightleftharpoons \text{PCl}_5 (g) \]
When she introduced 0.0811 moles of \(\text{PCl}_3 (g)\) and 0.115 moles of \(\text{Cl}_2 (g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{Cl}_2 (g)\) to be 0.0646 M.
Calculate the equilibrium constant, \(K_c\), she obtained for this reaction.
\[ K_c = \boxed{\phantom{K}} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e7279b6-864f-464c-a490-1592f397f56d%2F2d09893a-3d8d-4d7b-b8b0-e21ec2663200%2F0e7pi8x_processed.png&w=3840&q=75)
Transcribed Image Text:A student ran the following reaction in the laboratory at 531 K:
\[ \text{PCl}_3 (g) + \text{Cl}_2 (g) \rightleftharpoons \text{PCl}_5 (g) \]
When she introduced 0.0811 moles of \(\text{PCl}_3 (g)\) and 0.115 moles of \(\text{Cl}_2 (g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{Cl}_2 (g)\) to be 0.0646 M.
Calculate the equilibrium constant, \(K_c\), she obtained for this reaction.
\[ K_c = \boxed{\phantom{K}} \]
![A student ran the following reaction in the laboratory at 427 K:
\[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \]
When she introduced 3.96 moles of \(\text{PCl}_5(g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{Cl}_2(g)\) to be 0.0387 M.
Calculate the equilibrium constant, \(K_c\), she obtained for this reaction.
\[ K_c = \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e7279b6-864f-464c-a490-1592f397f56d%2F2d09893a-3d8d-4d7b-b8b0-e21ec2663200%2Farwifql_processed.png&w=3840&q=75)
Transcribed Image Text:A student ran the following reaction in the laboratory at 427 K:
\[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \]
When she introduced 3.96 moles of \(\text{PCl}_5(g)\) into a 1.00 liter container, she found the equilibrium concentration of \(\text{Cl}_2(g)\) to be 0.0387 M.
Calculate the equilibrium constant, \(K_c\), she obtained for this reaction.
\[ K_c = \]
Expert Solution
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Step 1: Find out Kc for the reaction
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