Suppose a 250. mL flask is filled with 0.40 mol of O, and 0.10 mol of NO. The following reaction becomes possible: N2(g) +O,(g) – 2No(g) The equilibrium constant K for this reaction is 7.40 at the temperature of the flask. Calculate the equilibrium molarity of N,. Round your answer to two decimal places.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.3QE: Describe a nonchemical system that is not in equilibrium, and explain why equilibrium has not been...
icon
Related questions
Question
**Chemical Equilibrium Problem: Determining the Equilibrium Molarity**

Suppose a 250. mL flask is filled with 0.40 mol of \( \text{O}_2 \) and 0.10 mol of \( \text{NO} \). The following reaction becomes possible:

\[ \text{N}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{NO}(g) \]

The equilibrium constant \( K \) for this reaction is 7.40 at the temperature of the flask.

**Task:**
Calculate the equilibrium molarity of \( \text{N}_2 \). Round your answer to two decimal places.

**Solution Input Box:**

\( \boxed{ \text{M} } \)
  \( \quad \quad \: \)
[ x ] \(\quad\) [ ↻ ] \(\quad\) [ ? ]

This educational example demonstrates how to use the equilibrium constant to find the equilibrium concentration of a reactant or product in a chemical reaction. 

**Approach:**
1. Calculate initial concentrations by dividing moles by volume (0.250 L).
2. Use the equilibrium constant expression derived from the balanced chemical equation.
3. Set up and solve the equation for the unknown concentration at equilibrium.
4. Round the final answer to two decimal places.

Through this process, students can practice applying their knowledge of chemical equilibria and stoichiometry.
Transcribed Image Text:**Chemical Equilibrium Problem: Determining the Equilibrium Molarity** Suppose a 250. mL flask is filled with 0.40 mol of \( \text{O}_2 \) and 0.10 mol of \( \text{NO} \). The following reaction becomes possible: \[ \text{N}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{NO}(g) \] The equilibrium constant \( K \) for this reaction is 7.40 at the temperature of the flask. **Task:** Calculate the equilibrium molarity of \( \text{N}_2 \). Round your answer to two decimal places. **Solution Input Box:** \( \boxed{ \text{M} } \) \( \quad \quad \: \) [ x ] \(\quad\) [ ↻ ] \(\quad\) [ ? ] This educational example demonstrates how to use the equilibrium constant to find the equilibrium concentration of a reactant or product in a chemical reaction. **Approach:** 1. Calculate initial concentrations by dividing moles by volume (0.250 L). 2. Use the equilibrium constant expression derived from the balanced chemical equation. 3. Set up and solve the equation for the unknown concentration at equilibrium. 4. Round the final answer to two decimal places. Through this process, students can practice applying their knowledge of chemical equilibria and stoichiometry.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Chemical Equilibrium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry: Principles and Practice
Chemistry: Principles and Practice
Chemistry
ISBN:
9780534420123
Author:
Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:
Cengage Learning
Physical Chemistry
Physical Chemistry
Chemistry
ISBN:
9781133958437
Author:
Ball, David W. (david Warren), BAER, Tomas
Publisher:
Wadsworth Cengage Learning,
World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
Chemistry
ISBN:
9781133109655
Author:
Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:
Brooks / Cole / Cengage Learning