Suppose a 500. mL flask is filled with 0.60 mol of CO, 0.30 mol of NO and 1.7 mol of CO,. The following reaction becomes possible: NO,(g) +CO(g) - NO(g) +CO,(g) The equilibrium constant K for this reaction is 0.953 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. ?
Suppose a 500. mL flask is filled with 0.60 mol of CO, 0.30 mol of NO and 1.7 mol of CO,. The following reaction becomes possible: NO,(g) +CO(g) - NO(g) +CO,(g) The equilibrium constant K for this reaction is 0.953 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. ?
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![Suppose a 500. mL flask is filled with 0.60 mol of CO, 0.30 mol of NO and 1.7 mol of CO,. The following reaction becomes possible:
NO,(g) +cO(g) - NO(g) +CO, (g)
The equilibrium constant K for this reaction is 0.953 at the temperature of the flask.
Calculate the equilibrium molarity of NO. Round your answer to two decimal places.
?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2c0fcb54-e854-49ef-aa69-39559bab08de%2F777157ad-e822-4a74-ab6b-0b94ee53bede%2F4xnk24g_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose a 500. mL flask is filled with 0.60 mol of CO, 0.30 mol of NO and 1.7 mol of CO,. The following reaction becomes possible:
NO,(g) +cO(g) - NO(g) +CO, (g)
The equilibrium constant K for this reaction is 0.953 at the temperature of the flask.
Calculate the equilibrium molarity of NO. Round your answer to two decimal places.
?
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