Suppose a 250. mL flask is filled with 0.70 mol of NO,, 0.40 mol of CO and 2.0 mol of CO ,. The following reaction becomes possible: NO,(s) + CO (g) → NO(g)+ CO,(g) The equilibrium constant K for this reaction is 1.04 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places.
Suppose a 250. mL flask is filled with 0.70 mol of NO,, 0.40 mol of CO and 2.0 mol of CO ,. The following reaction becomes possible: NO,(s) + CO (g) → NO(g)+ CO,(g) The equilibrium constant K for this reaction is 1.04 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places.
Introductory Chemistry: A Foundation
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Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter17: Equilibrium
Section: Chapter Questions
Problem 11QAP: . What does it mean to say that a state of chemical or physical equilibrium is dynamic?
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
Transcribed Image Text:Suppose a 250. mL flask is filled with 0.70 mol of NO,, 0.40 mol of CO and 2.0 mol of CO ,. The following reaction becomes possible:
NO,(3) + CO (g) - No(g)+ CO,(g)
The equilibrium constant K for this reaction is 1.04 at the temperature of the flask.
Calculate the equilibrium molarity of CO. Round your answer to two decimal places.
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