Homework Help is Here – Start Your Trial Now!
Science
Chemistry
Suppose a 250. mL flask is filled with 0.50 mol of CHCI3, 1.8 mol of HCl and 1.4 mol of CC14. The following reaction becomes possible: Cl,(g)+ CHCI,(g) -HCI (g)+ CCl,(g) The equilibrium constant K for this reaction is 0.525 at the temperature of the flask. Calculate the equilibrium molarity of Cl,. Round your answer to two decimal places.

Suppose a 250. mL flask is filled with 0.50 mol of CHCI3, 1.8 mol of HCl and 1.4 mol of CC14. The following reaction becomes possible: Cl,(g)+ CHCI,(g) -HCI (g)+ CCl,(g) The equilibrium constant K for this reaction is 0.525 at the temperature of the flask. Calculate the equilibrium molarity of Cl,. Round your answer to two decimal places.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question
100%
Suppose a 250. mL flask is filled with 0.50 mol of CHCI2, 1.8 mol of HCl and 1.4 mol of CCI4. The following reaction becomes possible: Cl,(g) + CHCI, (g) - HCI (g)+ CC14 (g) The equilibrium constant K for this reaction is 0.525 at the temperature of the flask. Calculate the equilibrium molarity of Cl,. Round your answer to two decimal places.
Transcribed Image Text:Suppose a 250. mL flask is filled with 0.50 mol of CHCI2, 1.8 mol of HCl and 1.4 mol of CCI4. The following reaction becomes possible: Cl,(g) + CHCI, (g) - HCI (g)+ CC14 (g) The equilibrium constant K for this reaction is 0.525 at the temperature of the flask. Calculate the equilibrium molarity of Cl,. Round your answer to two decimal places.
Expert Solution
Step 1

The equilibrium reaction given is,

Chemistry homework question answer, step 1, image 1

Given : Initial moles of CHCl3 = 0.50 mol

Initial moles of HCl = 1.8 mol

Initial moles of CCl4 = 1.4 mol

And volume of flask = 250 mL = 0.250 L                                                                (since 1 L = 1000 mL)

 

steps

Step by step

Solved in 3 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Chemical Equilibrium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS