Suppose a 250. mL flask is filled with 0.50 mol of CO, 0.10 mol of NO and 1.6 mol of CO2. The following reaction becomes possible: NO₂(g) + CO(g) NO(g) + CO₂(g) The equilibrium constant K for this reaction is 7.24 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places. M X

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Chapter1: Chemical Foundations
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Suppose a 

250.mL

 flask is filled with 

0.50mol

 of 

CO

0.10mol

 of 

NO

 and 

1.6mol

 of 

CO2

. The following reaction becomes possible:

+NO2gCOg

  

+NOgCO2g

The equilibrium constant 

K

 for this reaction is 

7.24

 at the temperature of the flask.

Calculate the equilibrium molarity of 

CO

. Round your answer to two decimal places.

Suppose a 250. mL flask is filled with 0.50 mol of CO, 0.10 mol of NO and 1.6 mol of CO2. The following reaction becomes possible:
NO₂(g) + CO(g) NO(g) + CO₂(g)
The equilibrium constant K for this reaction is 7.24 at the temperature of the flask.
Calculate the equilibrium molarity of CO. Round your answer to two decimal places.
M
X
Transcribed Image Text:Suppose a 250. mL flask is filled with 0.50 mol of CO, 0.10 mol of NO and 1.6 mol of CO2. The following reaction becomes possible: NO₂(g) + CO(g) NO(g) + CO₂(g) The equilibrium constant K for this reaction is 7.24 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places. M X
Suppose a 250. mL flask is filled with 0.50 mol of CO, 0.10 mol of NO and 1.6 mol of CO2. The following reaction becomes possible:
NO₂(g) + CO(g) → NO(g) + CO₂(g)
The equilibrium constant K for this reaction is 7.24 at the temperature of the flask.
Calculate the equilibrium molarity of CO. Round your answer to two decimal places.
M
X
Transcribed Image Text:Suppose a 250. mL flask is filled with 0.50 mol of CO, 0.10 mol of NO and 1.6 mol of CO2. The following reaction becomes possible: NO₂(g) + CO(g) → NO(g) + CO₂(g) The equilibrium constant K for this reaction is 7.24 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places. M X
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