Suppose a 500. mL flask is filled with 2.0 mol of NO, and 1.3 mol of NO. The following reaction becomes possible: NO, (g) + NO(g) → 2NO,(g) The equilibrium constant K for this reaction is 6.91 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. M
Suppose a 500. mL flask is filled with 2.0 mol of NO, and 1.3 mol of NO. The following reaction becomes possible: NO, (g) + NO(g) → 2NO,(g) The equilibrium constant K for this reaction is 6.91 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. M
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Calculating equilibrium composition from an equilibrium constant
Suppose a 500. mL flask is filled with 2.0 mol of NO, and 1.3 mol of NO. The following reaction becomes possible:
NO, (g) + NO(g) → 2NO, (g)
The equilibrium constant K for this reaction is 6.91 at the temperature of the flask.
Calculate the equilibrium molarity of NO. Round your answer to two decimal places.
Explanation
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Transcribed Image Text:O KINETICS AND EQUILIBRIUM
Calculating equilibrium composition from an equilibrium constant
Suppose a 500. mL flask is filled with 2.0 mol of NO, and 1.3 mol of NO. The following reaction becomes possible:
NO, (g) + NO(g) → 2NO, (g)
The equilibrium constant K for this reaction is 6.91 at the temperature of the flask.
Calculate the equilibrium molarity of NO. Round your answer to two decimal places.
Explanation
Check
02022 McGraw Hill LLC. All Rights Reserved. Terms of Use |P
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