Suppose a 500. mL flask is filled with 1.0 mol of CO, 1.8 mol of CO₂ and 0.90 mol of H₂. The following reaction becomes possibl CO(g) + H₂O(g) + CO₂(g) + H₂(g) The equilibrium constant K for this reaction is 0.932 at the temperature of the flask. Calculate the equilibrium molarity of CO2. Round your answer to two decimal places. M X

Chemistry: The Molecular Science
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Chapter12: Chemical Equilibrium
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Suppose a 500. mL flask is filled with 1.0 mol of CO, 1.8 mol of CO2 and 0.90 mol of H₂. The following reaction becomes possible:
CO(g) + H₂O(g) → CO₂(g) + H₂(g)
The equilibrium constant K for this reaction is 0.932 at the temperature of the flask.
Calculate the equilibrium molarity of CO2. Round your answer to two decimal places.
☐M
X
5
Transcribed Image Text:Suppose a 500. mL flask is filled with 1.0 mol of CO, 1.8 mol of CO2 and 0.90 mol of H₂. The following reaction becomes possible: CO(g) + H₂O(g) → CO₂(g) + H₂(g) The equilibrium constant K for this reaction is 0.932 at the temperature of the flask. Calculate the equilibrium molarity of CO2. Round your answer to two decimal places. ☐M X 5
Expert Solution
Step 1

Given equilibrium is 

CO(g) + H2O(g) ⇄ CO2(g) + H2(g) 

Initial moles of CO = 1.0 mol 

Initial moles of CO2 = 1.8 mol 

Initial moles of H2 = 0.90 mol 

Equilibrium constant , K = 0.932 

Volume of flask = 500. mL = 0.500 L 

Equilibrium molarity of CO2 = ? 

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