uppose a 250. mL flask is filled with 1.4 mol of H₂ and 1.1 mol of HCl. The following reaction becomes possible: H₂(g) + Cl₂(g) → 2HCl (g) he equilibrium constant K for this reaction is 0.292 at the temperature of the flask. alculate the equilibrium molarity of Cl₂. Round your answer to two decimal places. M X

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Suppose a 250. mL flask is filled with 1.4 mol of H₂ and 1.1 mol of HCl. The following reaction becomes possible:

\[ \text{H}_2(g) + \text{Cl}_2(g) \rightleftharpoons 2\text{HCl}(g) \]

The equilibrium constant \( K \) for this reaction is 0.292 at the temperature of the flask.

Calculate the equilibrium molarity of \( \text{Cl}_2 \). Round your answer to two decimal places.

\[ \text{ } \]

(Molarity Input Box)

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Transcribed Image Text:Suppose a 250. mL flask is filled with 1.4 mol of H₂ and 1.1 mol of HCl. The following reaction becomes possible: \[ \text{H}_2(g) + \text{Cl}_2(g) \rightleftharpoons 2\text{HCl}(g) \] The equilibrium constant \( K \) for this reaction is 0.292 at the temperature of the flask. Calculate the equilibrium molarity of \( \text{Cl}_2 \). Round your answer to two decimal places. \[ \text{ } \] (Molarity Input Box) (Icons: X for clearing input, and a circular arrow for resetting input)
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Step 1: Interpretation of datas :

G i v e n space comma
R e a c t i o n space colon space H subscript 2 left parenthesis g right parenthesis space plus C I subscript 2 left parenthesis g right parenthesis space rightwards harpoon over leftwards harpoon 2 H C I left parenthesis g right parenthesis
O b j e c t i v e space colon
C a l c u l a t e space e q u i l i b r i u m space m o l a r i t y space o f space C I subscript 2

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