Suppose a 500. mL flask is filled with 1.9 mol of O, and 1.8 mol of SO,. This reaction becomes possible: 2so, (g) + 0,(g) - 2so,(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O,. You can leave out the M symbol for molarity. so, 0, so, initial D. change equilibrium

Suppose a 500. mL flask is filled with 1.9 mol of O, and 1.8 mol of SO,. This reaction becomes possible: 2so, (g) + 0,(g) - 2so,(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O,. You can leave out the M symbol for molarity. so, 0, so, initial D. change equilibrium

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A mixture of 0.100 mol of SO2 and 0.100 mol of O2 is placed in a reaction container and allowed to react until equilibrium is established. 2 SO2 (g) + O2 (g) -> 2 SO3 At equilibrium, 0.0916 mol of SO3 is present. a. What is the composition of the equilibrium mixture in terms of moles of each substance present? (Hint: Stoichiometry!) b. If the container size is 3.0 L, what is the value of the equilibrium constant?
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Suppose a 250. mL flask is filled with 1.1 mol of NO,, 0.30 mol of CO and 1,3 mol of CO,. The following reaction becomes possible: NO, (g) +co(g) - NO(s)+Co,(g) The equilibrium constant K for this reaction is 7.86 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places.
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