Consider the insoluble compound silver chloride, AgCl. The silver ion also forms a complex with cyanide ions. Write a net ionic equation to show why the solubility of AgCl(s) increases in the presence of cyanide and calculate the equilibrium constant for this reaction. Solubility product constant data is found in the Chemistry References. For Ag(CN)2, Kf = 1.3x1021. Be sure to specify states such as (aq) or (s). K= + +

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**Topic: Solubility and Complex Ion Formation**

Consider the insoluble compound **silver chloride, AgCl**. The silver ion also forms a complex with **cyanide ions**. Write a net ionic equation to show why the solubility of AgCl(s) increases in the presence of cyanide and calculate the equilibrium constant for this reaction. Solubility product constant data is found in the Chemistry References.

For \( \text{Ag(CN)}_2^- \), \( K_f = 1.3 \times 10^{21} \). Be sure to specify states such as (aq) or (s).

\[
\boxed{} + \boxed{} \rightarrow \boxed{} + \boxed{}
\]

\[
K = \boxed{}
\]

**Explanation:**

In this problem, we are exploring the interaction between the insoluble compound silver chloride and cyanide ions, which lead to increased solubility of AgCl when cyanide is present. The formation of the complex ion \( \text{Ag(CN)}_2^- \) is characterized by a very high formation constant \( K_f \), indicating a strong tendency to form in solution.

**Key Steps:**

1. **Identify the static components:**
   - AgCl (s) as the insoluble compound.
   - \( \text{CN}^- \) as the complexing agent.

2. **Write the net ionic equation:**
   - Separate the dissolution and complex formation reactions.

3. **Calculate the equilibrium constant:**
   - Utilize the \( K_{sp} \) and \( K_f \) provided to determine the overall equilibrium constant for the process.

Understanding these procedures is crucial for students studying chemical equilibria, as it demonstrates how solubility can be manipulated through complex ion formation.
Transcribed Image Text:**Topic: Solubility and Complex Ion Formation** Consider the insoluble compound **silver chloride, AgCl**. The silver ion also forms a complex with **cyanide ions**. Write a net ionic equation to show why the solubility of AgCl(s) increases in the presence of cyanide and calculate the equilibrium constant for this reaction. Solubility product constant data is found in the Chemistry References. For \( \text{Ag(CN)}_2^- \), \( K_f = 1.3 \times 10^{21} \). Be sure to specify states such as (aq) or (s). \[ \boxed{} + \boxed{} \rightarrow \boxed{} + \boxed{} \] \[ K = \boxed{} \] **Explanation:** In this problem, we are exploring the interaction between the insoluble compound silver chloride and cyanide ions, which lead to increased solubility of AgCl when cyanide is present. The formation of the complex ion \( \text{Ag(CN)}_2^- \) is characterized by a very high formation constant \( K_f \), indicating a strong tendency to form in solution. **Key Steps:** 1. **Identify the static components:** - AgCl (s) as the insoluble compound. - \( \text{CN}^- \) as the complexing agent. 2. **Write the net ionic equation:** - Separate the dissolution and complex formation reactions. 3. **Calculate the equilibrium constant:** - Utilize the \( K_{sp} \) and \( K_f \) provided to determine the overall equilibrium constant for the process. Understanding these procedures is crucial for students studying chemical equilibria, as it demonstrates how solubility can be manipulated through complex ion formation.
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