Use the following information to answer the next 2 questions. 2CrO2 + 2H+ = Cr₂02-(aq) +H₂O(1) Kc yellow Select one: A technician analysed the above equilibrium mixture and determined that it contained 0.320 mol/L of dichromate ions and 0.0400 mol/L of chromate ions. The equilibrium law expression for this system is Ke = Kc = Kc = orange K₂ = [Cr₂O3-(aq)][H₂O(l)] [Cro2-(aq)][H+(aq)]² [Cro²-(aq)]²[H+(aq)]² [Cr₂O² (aq)] [Cr₂0²-(aq)][H₂O(l)] [Cro2-(aq)][2H+(aq)] = 9.00 x 105 [Cr₂O² (aq)] [Cro2-(aq)][H+(aq)]²
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
![Use the following information to answer the next 2 questions.
2CrO2 + 2H+ = Cr₂02-(aq) +H₂0 (1) K = 9.00 x 105
yellow
A technician analysed the above equilibrium mixture and determined that it
contained 0.320 mol/L of dichromate ions and 0.0400 mol/L of chromate ions.
The equilibrium law expression for this system is
Select one:
Kc =
K₂ =
Kc =
orange
Ke
[Cr₂0 (aq)][H₂O(1)]
[Cro2-(aq)]²[H+(aq)]²
[Cro²-(aq)][H+(aq)]²
[Cr₂0²-(aq)]
[Cr₂0²-(aq)][H₂0(1)]
[Cro2-(aq)][2H+(aq)]
[Cr₂0²-(aq)]
[Cro²-(aq)][H+(aq)]²
The concentration of hydrogen ions expressed in scientific notation is a.bc x 10-d
mol/L. The values of a, b, c, and d are
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