Determine the pH of a solution by constructing a BCA table, constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. Complete Parts 1-4 before submitting your answer. 1 3 4 NEXT > Two solutions are mixed: 40.0 mL of 0.500 M NH3 and 25.0 mL of 0.300 M HCI. Fill in the table with the appropriate value for each involved species to determine the moles of reactant and product after the reaction of the acid and base. Before (mol) Change (mol) After (mol) -0.0075 Initial (M) Change (M) Equilibrium (M) E 0.313 - x 0 0.0100 0 0.500 + x 40.0 0.115 + x NH3(aq) -0.0100 NH3(aq) + 0.500 2 0.500 - x 0.115-x 0.500 2 0.0125 : on by constructing a BCA table, constructing an ICE table, ant expression, and using this information to determine the pH. Complete Parts 1-4 before submitting your answer. -■· 0.300 + < PREV 1 3 NEXT Based on the result of the acid-base reaction (Part 1), set up the ICE table in order to determine the unknown concentrations of all reactants and products. 0.300 + x 25.0 H₂O(1) -0.0125 H*(aq) 0.192 0.300 0.300 - x 0.0200 0.300 - x -0.0200 0.313 0.192 + x 4 NH4*(aq) RESET OH(aq) + NH4* (aq) 0.115 0.0075 0.192 - x RESET +x 0.313 + x >
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

![Determine the pH of a solution by constructing a BCA table, constructing an ICE table,
writing the equilibrium constant expression, and using this information to determine the
pH. Complete Parts 1-4 before submitting your answer.
< PREV
1
2
NEXT >
The value of Kb for NH3 is 1.8 x 10-5. Based on your ICE table (Part 2) and the definition of Kb, set up the
expression for Kb in order to determine the unknown. Each reaction participant must be represented by one
tile. Do not combine terms.
[0]
[0.500 + x]
[0.115 + x]
[0.500]
0
[0.500 -x]
0.693
[0.115-x]
Kb
=
3.00 x 10-5
[0.300]
[0.300 + x]
[0.192]
[0.300 -x]
10.41
3
pH =
[0.313]
3.32 x 10-1⁰
=
[0.192 + x]
Determine the pH of a solution by constructing a BCA table, constructing an ICE table,
writing the equilibrium constant expression, and using this information to determine the
pH. Complete Parts 1-4 before submitting your answer.
1.8 x 10-5
< PREV
1
2
Based on your ICE table (Part 2) and the equilibrium expression for Kb (Part 3), determine the pH of
solution.
4.52
3
4
[0.115]
[0.192 -x] [0.313 + x]
9.48
RESET
[2x]
0.500
[0.313 -x]
RESET
0.301](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F84d3fdf0-b73f-4040-a051-97beff994827%2F23c73121-1366-4721-99c0-0f9d78dafcba%2Fzu8bhg7o_processed.png&w=3840&q=75)
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