A solution is prepared that is initially 0.45 M in trimethylamine ((CH3)3N), i a weak base, and 0.37M in trimethylammonium bromide ((CH3)¸NHBr). Complete the reaction table below, so that you could use it to calculate the pH of this solution. Use x to stand for the unknown change in [OH]. You can leave out the M symbol for molarity. initial change final [(CH,),N] [(CH,),NH] lon 0 0 0 0 0 0 Olo
A solution is prepared that is initially 0.45 M in trimethylamine ((CH3)3N), i a weak base, and 0.37M in trimethylammonium bromide ((CH3)¸NHBr). Complete the reaction table below, so that you could use it to calculate the pH of this solution. Use x to stand for the unknown change in [OH]. You can leave out the M symbol for molarity. initial change final [(CH,),N] [(CH,),NH] lon 0 0 0 0 0 0 Olo
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A solution is prepared that is initially \(0.45M\) in trimethylamine \(\left( \text{(CH}_3\right)_3 \text{N})\), a weak base, and \(0.37M\) in trimethylammonium bromide \(\left( \text{(CH}_3\right)_3 \text{NHBr})\).
Complete the reaction table below, so that you could use it to calculate the pH of this solution.
Use \(x\) to stand for the unknown change in \([ \text{OH}^-]\). You can leave out the \(M\) symbol for molarity.
\[
\begin{array}{|c|c|c|c|}
\hline
& [(\text{CH}_3)_3 \text{N}] & [(\text{CH}_3)_3 \text{NH}^+] & [\text{OH}^-] \\
\hline
\text{initial} & 0.45 & 0.37 & 0 \\
\hline
\text{change} & -x & +x & +x \\
\hline
\text{final} & 0.45 - x & 0.37 + x & x \\
\hline
\end{array}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa60cc6ce-11de-444a-af29-e9eb1b50e640%2Fdc99a1d2-e156-4876-bfad-3435c732e51c%2Ftbjsho_processed.png&w=3840&q=75)
Transcribed Image Text:A solution is prepared that is initially \(0.45M\) in trimethylamine \(\left( \text{(CH}_3\right)_3 \text{N})\), a weak base, and \(0.37M\) in trimethylammonium bromide \(\left( \text{(CH}_3\right)_3 \text{NHBr})\).
Complete the reaction table below, so that you could use it to calculate the pH of this solution.
Use \(x\) to stand for the unknown change in \([ \text{OH}^-]\). You can leave out the \(M\) symbol for molarity.
\[
\begin{array}{|c|c|c|c|}
\hline
& [(\text{CH}_3)_3 \text{N}] & [(\text{CH}_3)_3 \text{NH}^+] & [\text{OH}^-] \\
\hline
\text{initial} & 0.45 & 0.37 & 0 \\
\hline
\text{change} & -x & +x & +x \\
\hline
\text{final} & 0.45 - x & 0.37 + x & x \\
\hline
\end{array}
\]
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