A solution is prepared that is initially 0.45 M in trimethylamine ((CH3)3N), i a weak base, and 0.37M in trimethylammonium bromide ((CH3)¸NHBr). Complete the reaction table below, so that you could use it to calculate the pH of this solution. Use x to stand for the unknown change in [OH]. You can leave out the M symbol for molarity. initial change final [(CH,),N] [(CH,),NH] lon 0 0 0 0 0 0 Olo
A solution is prepared that is initially 0.45 M in trimethylamine ((CH3)3N), i a weak base, and 0.37M in trimethylammonium bromide ((CH3)¸NHBr). Complete the reaction table below, so that you could use it to calculate the pH of this solution. Use x to stand for the unknown change in [OH]. You can leave out the M symbol for molarity. initial change final [(CH,),N] [(CH,),NH] lon 0 0 0 0 0 0 Olo
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 8ALQ: You have a solution of the weak acid HA and add some of the salt NaA to it. What are the major...
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![A solution is prepared that is initially 0.45M in trimethylamine ((CH3)N), a weak base, and 0.37M in trimethylammonium bromide
Complete the reaction table below, so that you could use it to calculate the pH of this solution.
Use x to stand for the unknown change in [OH-]. You can leave out the M symbol for molarity.
initial
change
final
[(CH₂)₂N] [(CH₂)₂
3
[(CH,),NH
0
0
0
0
0
[OH-]
0
0
0
((CH3)₂NHBr](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa60cc6ce-11de-444a-af29-e9eb1b50e640%2Fdc99a1d2-e156-4876-bfad-3435c732e51c%2Ftbjsho_processed.png&w=3840&q=75)
Transcribed Image Text:A solution is prepared that is initially 0.45M in trimethylamine ((CH3)N), a weak base, and 0.37M in trimethylammonium bromide
Complete the reaction table below, so that you could use it to calculate the pH of this solution.
Use x to stand for the unknown change in [OH-]. You can leave out the M symbol for molarity.
initial
change
final
[(CH₂)₂N] [(CH₂)₂
3
[(CH,),NH
0
0
0
0
0
[OH-]
0
0
0
((CH3)₂NHBr
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