Fill in the blanks to show how you would solve for the pH of a 0.10 M aqueous solution of the weak acid HA. For the table and the equilibrium expression, do not ignore x. 0.10 Initial POH 0.10-x Concentration (M) Change 2x² 0.10 - 2x 4x² HA(aq) X + (0.10 - x)² (0.10-2x)² 2x H₂O(1) 0 4x A¯(aq) x² 0.10- x² + + pH 0.10 + x H3O*(aq)
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
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Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
![### Solving for the pH of a 0.10 M Aqueous Solution of the Weak Acid HA
#### Instructions:
Fill in the blanks to show how you would solve for the pH of a 0.10 M aqueous solution of the weak acid HA. For the table and the equilibrium expression, do not ignore x.
#### Provided Options:
- 0.10
- 0.10 - x
- 0.10 - 2x
- x
- 2x
- 0
- x²
- pH
- pOH
- 2x²
- 4x²
- (0.10 - x)²
- 4x
- 0.10 - x²
- 0.10 + x
#### ICE Table for the Reaction \( \text{HA}(\text{aq}) + \text{H}_2\text{O}(\ell) \rightleftharpoons \text{A}^-(\text{aq}) + \text{H}_3\text{O}^+(\text{aq}) \)
| Concentration (M) | HA(aq) | + H2O(l) | ↔ | A<sup>-</sup>(aq) | + H3O<sup>+</sup>(aq) |
|--------------------|--------|----------|---|-------------------|---------------------|
| **Initial** | 0.10 | - | - | 0 | 0 |
| **Change** | - x | - | - | + x | + x |
| **Equilibrium** | 0.10 - x | - | - | x | x |
At equilibrium, the concentrations of the ions/products and reactants are as follows:
- HA: \( 0.10 - x \) M
- \( \text{A}^- \): \( x \) M
- \( \text{H}_3\text{O}^+ \): \( x \) M
#### Equilibrium Expression:
\[ K_a = \frac{[\text{A}^-][\text{H}_3\text{O}^+]}{[\text{HA}]} \]
Using the concentrations from the equilibrium row, we get:
\[ K_a = \frac{x \cdot x}{0.10 - x} = \frac](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc8fc0129-1b11-49f3-869a-8ad1c019dc55%2Fddd87e6f-139d-450f-821d-22667bd253e1%2Ftato6t_processed.jpeg&w=3840&q=75)
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