A chemist titrates 220.0 mL of a 0.6099M trimethylamine ((CH3)N) solution with 0.2791 M HCl solution at 25 °C. Calculate the pH at equivalence. The pK, of trimethylamine is 4.19. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume o HCl solution added. pH = 0 X
A chemist titrates 220.0 mL of a 0.6099M trimethylamine ((CH3)N) solution with 0.2791 M HCl solution at 25 °C. Calculate the pH at equivalence. The pK, of trimethylamine is 4.19. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume o HCl solution added. pH = 0 X
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 55P
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![A chemist titrates 220.0 mL of a 0.6099M trimethylamine ((CH3)N) solution with 0.2791 M HCl solution at 25 °C.
Calculate the pH at equivalence. The p K of trimethylamine is 4.19.
Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of
HCl solution added.
pH = 0
Ś](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0c04aa6a-da54-4078-93fd-bbe607ae33f4%2F3c1c0f28-a133-4627-8dab-e0fb3763fbaf%2F6d9gc6l_processed.png&w=3840&q=75)
Transcribed Image Text:A chemist titrates 220.0 mL of a 0.6099M trimethylamine ((CH3)N) solution with 0.2791 M HCl solution at 25 °C.
Calculate the pH at equivalence. The p K of trimethylamine is 4.19.
Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of
HCl solution added.
pH = 0
Ś
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