Determine the Kb for a base by constructing an ICE table and using this information to construct and solve the equilibrium constant expression. Complete Parts 1-2 before submitting your answer. NEXT The pH for a 0.0160 M solution of CH3C6H4NH₂ is 8.600. Fill in the ICE table with the appropriate value for each involved species to determine the unknown concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) -2.50 × 10-9 CH3C6H4NH₂(aq) + 0 1 3.98 x 10-6 0.0160 -3.98 x 10-6 8.60 5.4 H₂O(1) -8.60 -5.4 = 2 OH-(aq) 0.93 -0.93 + CH3C6H4NH3 + (aq) RESET 2.50 × 10-9

Determine the Kb for a base by constructing an ICE table and using this information to construct and solve the equilibrium constant expression. Complete Parts 1-2 before submitting your answer. NEXT The pH for a 0.0160 M solution of CH3C6H4NH₂ is 8.600. Fill in the ICE table with the appropriate value for each involved species to determine the unknown concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) -2.50 × 10-9 CH3C6H4NH₂(aq) + 0 1 3.98 x 10-6 0.0160 -3.98 x 10-6 8.60 5.4 H₂O(1) -8.60 -5.4 = 2 OH-(aq) 0.93 -0.93 + CH3C6H4NH3 + (aq) RESET 2.50 × 10-9

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Determine the Kb for a base by constructing an ICE table and using this information to
construct and solve the equilibrium constant expression. Complete Parts 1-2 before
submitting your answer.
Initial (M)
Change (M)
Equilibrium (M)
NEXT
The pH for a 0.0160 M solution of CH3C6H4NH₂ is 8.600. Fill in the ICE table with the appropriate value for
each involved species to determine the unknown concentrations of all reactants and products.
-2.50 × 10-9
1
CH3C6H4NH₂(aq) +
0
3.98 x 10-6
0.0160
-3.98 x 10-6
8.60
5.4
H₂O(1)
-8.60
-5.4
2
=
OH-(aq)
0.93
-0.93
+ CH3C6H4NH3 + (aq)
RESET
2.50 × 10-9

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