You have a 5MVA three-phase 4160/480V transformer that has an impedance of 4.63%. a. Calculate input current at full load b. Calculate output current and output voltage at full load c. Calculate the line - to - line short circuit current the transformer can supply.
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- Find full load current..A 250/125 V, five kVA single-phase transformer has a primary resistance of 0.2 ohms and reactance of 0.75 ohms. The secondary resistance is 0.05 ohm and reactance of 0.2 ohms.a) Determine its regulation while supplying full load on 0.8 leading p.f.b) The secondary terminal voltage on full load and 0.8 leading p.f.Ans.: -0.4.88%; 131.16. A 1-phase full converter delivers ripple free current to RL load with R=1592. The source voltage is 230V, 50Hz, for a=30°. Determine rectification efficiency, voltage ripple factor displacement factor, and power factor
- 3. A 3200/400 single-phase transformer has winding resistance and reactance of 30 and 132 respectively in the primary and 0.0292 and 0.0652 in the secondary. Express these in terms of (a) primary alone, (b) secondary alone. (ans. (a) 4.282, 17.16; (b) 0.067, 0.268)14. The output current corresponding to maximum efficiency for a transformer having core loss of 100 W and equivalent resistance referred to secondary of 0.2: is .. ampere. (a)20 (b)25 (c)5 (d) 400 15. At relatively light loads, transformer efficiency is low because (a) secondary output is low (b) transformer losses are high (c) fixed loss is high in proportion to the output (d) Cu loss is small. 16. When a 400-Hz transformer is operated at 50HZ its kVA rating is (a) reduced to 1/8 (b) increased 8 times (c) unaffected (d) increased 64 times. 17. The voltage applied to the h.v. side of a transformer during short-circuit test i of its rated voltage. The core loss will be..percent of the rated core loss. (a)4 (b) 0.4 (c)0.25 (d)0.04 18. The main purpose of performing open-circuit test on a transformer is to meas its (a) Cu loss (b) core loss (c) total loss (d) both Cu and total losses. 19. During short-circuit test, the iron loss of a transformer is negligible because (a) the entire input…If we increase the load than core loss and copper loss will... Decrease Increase Remain same
- The windings of an 11500/2300V two winding transformer are connected in series, with 11500 V as the supply to the primary, to create an autotransformer. What is the voltage output of the resulting step-up autotransformer when Ip and Is are 10 A and 50 A, respectively?Can you solve D and E1. A transformer takes 10 A on no-load at a power factor of 0.1. The turn ratio is 4 : 1 (step down). Ifaload is supplied by the secondary at 200 A and p.f. of 0.8, find the primary current and power factor(internal voltage drops in transformer are to be ignored).
- dc tansformdQ:A 50 Hz, single phase transformer has a tums ratio of 6.The resistances are 0.9 2 and 0.03 Q and reactances are 5 2 and 0.13 Q for high voltage and low voltage windings respectively.Find : i)The voltage to be applied to high voltage side to obtain full load current of 200 A in the low voltage winding on short circuit. ii) The power factor on short circuit.Design a flyback converter for an input of 24 V and output of 40 W at 40V. Specify the transformer turns and magnetizing inductance, switching frequency and capacitor to limit the ripple voltage less than 0.5%.