17:58 O 1 Q + given is 5 volts. Don't know where i am wrong. 5 ww 2A 12+ ww R ww b 6 V (a) ww 11 D D Single comment thread 56 30 V Fig. 2. See full discussion • Hopeless_Engineer24 OP 2d ago • Can you please tell why? Is it because there's no current flow in the branch so I should take positive? 1 ☐ Reply • Falgmed 2d ago • It's because Vcb = 6 and Vbc = -6, reference matters 2 3 Reply crazybehind • • 2d ago • Zalo Your fourth to last equation has +Vcb. Vcb = Vc - Vb. Vc is higher than Vb just by virtue of how that source is oriented. The fact that the branch has zero current has nothing to do with that. The zero current just let's you ignore the resistor 'R'.

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.30P: Reconsider Problem 3.29. If Va,VbandVc are a negative-sequence set, how would the voltage and...
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Question
17:58 O
1
Q +
given is 5 volts. Don't know where i am wrong.
5
ww
2A
12+
ww
R
ww
b
6 V
(a)
ww
11
D
D
Single comment thread
56
30 V
Fig. 2.
See full discussion
•
Hopeless_Engineer24 OP 2d ago •
Can you please tell why? Is it because there's no
current flow in the branch so I should take positive?
1
☐ Reply
•
Falgmed 2d ago •
It's because Vcb = 6 and Vbc = -6, reference
matters
2 3
Reply
crazybehind
•
• 2d ago •
Zalo
Your fourth to last equation has +Vcb. Vcb = Vc -
Vb. Vc is higher than Vb just by virtue of how that
source is oriented.
The fact that the branch has zero current has
nothing to do with that. The zero current just let's
you ignore the resistor 'R'.
Transcribed Image Text:17:58 O 1 Q + given is 5 volts. Don't know where i am wrong. 5 ww 2A 12+ ww R ww b 6 V (a) ww 11 D D Single comment thread 56 30 V Fig. 2. See full discussion • Hopeless_Engineer24 OP 2d ago • Can you please tell why? Is it because there's no current flow in the branch so I should take positive? 1 ☐ Reply • Falgmed 2d ago • It's because Vcb = 6 and Vbc = -6, reference matters 2 3 Reply crazybehind • • 2d ago • Zalo Your fourth to last equation has +Vcb. Vcb = Vc - Vb. Vc is higher than Vb just by virtue of how that source is oriented. The fact that the branch has zero current has nothing to do with that. The zero current just let's you ignore the resistor 'R'.
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