17:58 O 1 Q + given is 5 volts. Don't know where i am wrong. 5 ww 2A 12+ ww R ww b 6 V (a) ww 11 D D Single comment thread 56 30 V Fig. 2. See full discussion • Hopeless_Engineer24 OP 2d ago • Can you please tell why? Is it because there's no current flow in the branch so I should take positive? 1 ☐ Reply • Falgmed 2d ago • It's because Vcb = 6 and Vbc = -6, reference matters 2 3 Reply crazybehind • • 2d ago • Zalo Your fourth to last equation has +Vcb. Vcb = Vc - Vb. Vc is higher than Vb just by virtue of how that source is oriented. The fact that the branch has zero current has nothing to do with that. The zero current just let's you ignore the resistor 'R'.

17:58 O 1 Q + given is 5 volts. Don't know where i am wrong. 5 ww 2A 12+ ww R ww b 6 V (a) ww 11 D D Single comment thread 56 30 V Fig. 2. See full discussion • Hopeless_Engineer24 OP 2d ago • Can you please tell why? Is it because there's no current flow in the branch so I should take positive? 1 ☐ Reply • Falgmed 2d ago • It's because Vcb = 6 and Vbc = -6, reference matters 2 3 Reply crazybehind • • 2d ago • Zalo Your fourth to last equation has +Vcb. Vcb = Vc - Vb. Vc is higher than Vb just by virtue of how that source is oriented. The fact that the branch has zero current has nothing to do with that. The zero current just let's you ignore the resistor 'R'.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.30P: Reconsider Problem 3.29. If Va,VbandVc are a negative-sequence set, how would the voltage and...

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