X 5. 416 REED'S APPLIED MECHANICS FOR ENGINEERS graving of 4. Working in cm, and taking moments about the centre of sheave arranged vertically: = y = Σ moments of areas Σ areas 0.7854 x 502 x00-7854 x 12.52 x 10 137:815 2 y = 0-10 42-1 = -10 15 = -0.667cm 0.7854 × 50²-0-7854 x 12.52 The minus sign means that the centre of gravity is in the opposite direction to the hole, from the centre of the sheave, . CG = 6.67 mm from centre. Ans. Alternatively, if moments are taken about the thin edge of the sheave, y from edge 50² 0.7854 × 502 ×(250-7854 x 12.52 15 0.7854 × 50²-0-7854 x 12-52 42 × 25-15 35mm 385 = 42 - 1 15 = 25.667 cm from edge = 6.67 mm from centre à 420mm- 20 -120mm 100ma. Ommy 70mm
X 5. 416 REED'S APPLIED MECHANICS FOR ENGINEERS graving of 4. Working in cm, and taking moments about the centre of sheave arranged vertically: = y = Σ moments of areas Σ areas 0.7854 x 502 x00-7854 x 12.52 x 10 137:815 2 y = 0-10 42-1 = -10 15 = -0.667cm 0.7854 × 50²-0-7854 x 12.52 The minus sign means that the centre of gravity is in the opposite direction to the hole, from the centre of the sheave, . CG = 6.67 mm from centre. Ans. Alternatively, if moments are taken about the thin edge of the sheave, y from edge 50² 0.7854 × 502 ×(250-7854 x 12.52 15 0.7854 × 50²-0-7854 x 12-52 42 × 25-15 35mm 385 = 42 - 1 15 = 25.667 cm from edge = 6.67 mm from centre à 420mm- 20 -120mm 100ma. Ommy 70mm
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter1: Introduction To Statics
Section: Chapter Questions
Problem 1.12P: A differential equation encountered in the vibration of beams is d4ydx4=2D where x = distance...
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An eccentric sheave of uniform thickness is 500 mm diameter, the hole for the shaft is 125 mm diameter and its center is 100 mm from the center of the sheave. Calculate the position of the center of gravity of the sheave from its geometrical center.
Hi, I already have the answer but am confused one some steps. I'm wondering how they simplified the equation (where I wrote 1 and 2) and where the numbest came from that I have circled in the questions. Picture attached. Please explain and break it down for me. Thanks
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