The ends of the 0.44-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.47 m/s and anacceleration of 0.45 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative ifclockwise) of the bar and the acceleration of end A (positive if up, negative if down).23°0.44 m100°Answers:BaB = 0.45 m/s²UB=0.47 m/sa =rad/s²

1. Determine the angular acceleration (α)Step 1:The bar has a length L=0.44 mAngle at end A =…

Answered: The ends of the 0.44-m bar remain in…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The answer to the problem is 2.33 rad/s. Please show me how to get the final answer
The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down). 21 101° Answers: a = aA= i i 0.62 m Bag=0.37m/s² -2.2045 1.1279 UB=0.58 m/s rad/s² m/s²
X Incorrect The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down). A 21° 101° Answers: a = aA = i 0.62 m Bag=0.37 m/s² 2.2045 1.1279 UB=0.58 m/s rad/s² m/s²
X Incorrect The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down). 21 101° Answers: a = aA 0.62 m B B=0.37m/s² -0.319 i 0.432 UB=0.58 m/s rad/s² m/s²
Bar OC rotates with a clockwise angular velocity woc = 2.9 rad/s and a counterclockwise angular acceleration đoc = 1.5 rad/s². The bar OC is a slotted member which accommodates the pin A attached to the sector. Determine the angular velocity w and the angular acceleration a of the sector. The angular velocity and the angular acceleration are positive if counterclockwise, negative if clockwise. Assume OA = 415 mm, d = 320 mm, e = 37°. A B d aoc Answers: rad/s W = 4.71 i -34.6 rad/s?
The shaft of the wheel unit rolls without slipping and ao 8 ft/sec2 to the left, respectively, determine the accelerations of points A and D. on the fixed horizontal surface. If the velocity and acceleration of point O are vo 3 ft/sec to the right Assume r 2.3 in., R 13 in. R Answers: j) ft/sec2 aA i j) ft/sec2 i+ ap
Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. The disk has a constant angular velocity of 30 rad/s clockwise. D 2.8 in. 10 in. For each of these values of e, determine the corresponding value of the angular velocity of bar BD. Take rA = 2.8 in. and /BD = 10 in. The corresponding value of the angular velocity of bar BD for 6 = 22.9° is The corresponding value of the angular velocity of bar BD for 0 = 192.6° is rad/s (Click to select) rad/s (Click to select)
An overhead door is guided by wheels at A and B that roll in horizontal and vertical tracks. When 0= 40°, the velocity of wheel Bis 2.4 ft/s upward. 5 ft 5 ft Determine the angular velocity of the door. (You must provide an answer before moving on to the next part.) The angular velocity of the door is rad/s.
Nilo
The center O of the disk has the velocity and acceleration shown in the figure. If the disk rolls without slipping on the horizontal surface, determine the velocity of A and the acceleration of B for the instant represented. Assume a = 6.5 m/s², v = 2.3 m/s, b = 0.4 m, 0 = 40°. Answers: VA = i+ i j) m/s i + i j) m/s² ag = i (i
Needs Complete solution please.
Bar OC rotates with a clockwise angular velocity woc = 2.9 rad/s and a counterclockwise angular acceleration doc = 1.5 rad/s². The bar OC is a slotted member which accommodates the pin A attached to the sector. Determine the angular velocity w and the angular acceleration a of the sector. The angular velocity and the angular acceleration are positive if counterclockwise, negative if clockwise. Assume OA = 415 mm, d = 320 mm, 0 = 37°. A B d aoc Answers: i rad/s W = rad/s?

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