**Problem Statement:**The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration α (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down).**Diagram Description:**The diagram shows a bar of length 0.62 m. The bar is inclined with end A at an angle of 21° from the vertical, and end B at an angle of 101° from the horizontal. End B has the following parameters:- Acceleration, aB = 0.37 m/s² directed downwards along the slope at end B.- Velocity, vB = 0.58 m/s directed downwards along the slope at end B.The bar remains in contact with the ground at end A.**Answers:**- Angular acceleration, α: \[ α = -2.2045 \, \text{rad/s}^2 \]- Acceleration of end A, \( a_A \): \[ a_A = 1.1279 \, \text{m/s}^2 \]The negative value for angular acceleration (α) suggests that the bar is rotating clockwise, while the positive acceleration for end A indicates it is moving upwards.

Answered: Image /qna-images/answer/492c9729-83a8-412c-af58-1cdf7d7c5d2d.jpg

The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s2 in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down).

The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s2 in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down).

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

**Problem Statement:**
The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration α (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down).

**Diagram Description:**
The diagram shows a bar of length 0.62 m. The bar is inclined with end A at an angle of 21° from the vertical, and end B at an angle of 101° from the horizontal. End B has the following parameters:
- Acceleration, aB = 0.37 m/s² directed downwards along the slope at end B.
- Velocity, vB = 0.58 m/s directed downwards along the slope at end B.
The bar remains in contact with the ground at end A.

**Answers:**
- Angular acceleration, α:
\[
α = -2.2045 \, \text{rad/s}^2
\]

- Acceleration of end A, \( a_A \):
\[
a_A = 1.1279 \, \text{m/s}^2
\]

The negative value for angular acceleration (α) suggests that the bar is rotating clockwise, while the positive acceleration for end A indicates it is moving upwards.

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