The ends of the 0.63-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.40 m/s and an acceleration of 0.47 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down). 28 105° 0.63 m B -ag=0.47m/s² UB=0.40 m/s

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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### Problem Statement:

The ends of the 0.63-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.40 m/s and an acceleration of 0.47 m/s² in the directions shown. Determine the angular acceleration α (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down).

### Diagram Explanation:

The provided diagram illustrates a bar leaning against a wall, forming an angle of 28° with the vertical wall and an angle of 105° with the horizontal ground. The bar's length is 0.63 meters. The diagram also shows the following data for end B:

- Velocity \(v_B\) = 0.40 m/s (to the right)
- Acceleration \(a_B\) = 0.47 m/s² (to the right)

### Required Calculations:
1. **Determine the angular acceleration (α) of the bar:**
   - Use the given values for velocity and acceleration of end B to calculate the angular acceleration of the bar considering counterclockwise as positive and clockwise as negative.

2. **Compute the acceleration (a_A) of end A:**
   - Determine the linear acceleration of end A, with the positive direction being upward and the negative direction being downward.

### Answers:

| \(\alpha \) |   | rad/s²   |
|-------------|---|----------|
| \(a_A \)    |   | m/s²     |

To complete the calculations for these values, use the kinematic equations and principles of rotational motion as required for solving problems in mechanics involving rigid bodies.
Transcribed Image Text:### Problem Statement: The ends of the 0.63-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.40 m/s and an acceleration of 0.47 m/s² in the directions shown. Determine the angular acceleration α (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down). ### Diagram Explanation: The provided diagram illustrates a bar leaning against a wall, forming an angle of 28° with the vertical wall and an angle of 105° with the horizontal ground. The bar's length is 0.63 meters. The diagram also shows the following data for end B: - Velocity \(v_B\) = 0.40 m/s (to the right) - Acceleration \(a_B\) = 0.47 m/s² (to the right) ### Required Calculations: 1. **Determine the angular acceleration (α) of the bar:** - Use the given values for velocity and acceleration of end B to calculate the angular acceleration of the bar considering counterclockwise as positive and clockwise as negative. 2. **Compute the acceleration (a_A) of end A:** - Determine the linear acceleration of end A, with the positive direction being upward and the negative direction being downward. ### Answers: | \(\alpha \) | | rad/s² | |-------------|---|----------| | \(a_A \) | | m/s² | To complete the calculations for these values, use the kinematic equations and principles of rotational motion as required for solving problems in mechanics involving rigid bodies.
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