The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down).
The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down).
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![### Angular and Linear Acceleration in a Rotating Bar
#### Problem Statement:
The ends of the 0.62-m bar remain in contact with their respective support surfaces. End \( B \) has a velocity of \( 0.58 \, \text{m/s} \) and an acceleration of \( 0.37 \, \text{m/s}^2 \) in the directions shown. Determine the angular acceleration \( \alpha \) (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end \( A \) (positive if up, negative if down).
#### Figure Explanation:
An image is provided showing a bar of length \( 0.62 \, \text{m} \) inclined at \( 21^\circ \) to the vertical on the left side (end \( A \)) and \( 101^\circ \) to the horizontal on the right side (end \( B \)). End \( B \) has:
- A velocity \( v_B = 0.58 \, \text{m/s} \) directed horizontally to the left.
- An acceleration \( a_B = 0.37 \, \text{m/s}^2 \) directed vertically downward.
#### Calculations:
Students are required to determine:
1. The angular acceleration \( \alpha \) of the bar.
2. The acceleration \( a_A \) of the end \( A \).
#### Input Fields:
- **Angular acceleration (\(\alpha\)):**
[Input Box] ``\(\displaystyle \text{rad/s}^2\)``
- **Acceleration of \( A \) (\(a_A\)):**
[Input Box] ``\(\displaystyle \text{m/s}^2\)``
#### Answers:
To solve this problem, use the rotational motion equations and kinematic relationships between the ends of the bar. The following steps can guide the calculations:
1. **Determine Angular Acceleration \( \alpha \):**
- Use the relationship between the linear acceleration of end \( B \) and angular acceleration.
- Apply the geometric constraints provided by the angles.
2. **Acceleration of End \( A \) (\(a_A\)):**
- Calculate based on the angular acceleration and the known conditions at end \( B \).
Students should apply the principles of rigid body dynamics to derive the equations for \( \alpha \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b7dd8f1-dbab-4607-8b33-bde9974f18c9%2Fc95f15f1-feaf-42c9-a2d8-d111cb83b37d%2F9sf6fe_processed.png&w=3840&q=75)
Transcribed Image Text:### Angular and Linear Acceleration in a Rotating Bar
#### Problem Statement:
The ends of the 0.62-m bar remain in contact with their respective support surfaces. End \( B \) has a velocity of \( 0.58 \, \text{m/s} \) and an acceleration of \( 0.37 \, \text{m/s}^2 \) in the directions shown. Determine the angular acceleration \( \alpha \) (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end \( A \) (positive if up, negative if down).
#### Figure Explanation:
An image is provided showing a bar of length \( 0.62 \, \text{m} \) inclined at \( 21^\circ \) to the vertical on the left side (end \( A \)) and \( 101^\circ \) to the horizontal on the right side (end \( B \)). End \( B \) has:
- A velocity \( v_B = 0.58 \, \text{m/s} \) directed horizontally to the left.
- An acceleration \( a_B = 0.37 \, \text{m/s}^2 \) directed vertically downward.
#### Calculations:
Students are required to determine:
1. The angular acceleration \( \alpha \) of the bar.
2. The acceleration \( a_A \) of the end \( A \).
#### Input Fields:
- **Angular acceleration (\(\alpha\)):**
[Input Box] ``\(\displaystyle \text{rad/s}^2\)``
- **Acceleration of \( A \) (\(a_A\)):**
[Input Box] ``\(\displaystyle \text{m/s}^2\)``
#### Answers:
To solve this problem, use the rotational motion equations and kinematic relationships between the ends of the bar. The following steps can guide the calculations:
1. **Determine Angular Acceleration \( \alpha \):**
- Use the relationship between the linear acceleration of end \( B \) and angular acceleration.
- Apply the geometric constraints provided by the angles.
2. **Acceleration of End \( A \) (\(a_A\)):**
- Calculate based on the angular acceleration and the known conditions at end \( B \).
Students should apply the principles of rigid body dynamics to derive the equations for \( \alpha \)
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