The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down).

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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### Angular and Linear Acceleration in a Rotating Bar

#### Problem Statement:
The ends of the 0.62-m bar remain in contact with their respective support surfaces. End \( B \) has a velocity of \( 0.58 \, \text{m/s} \) and an acceleration of \( 0.37 \, \text{m/s}^2 \) in the directions shown. Determine the angular acceleration \( \alpha \) (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end \( A \) (positive if up, negative if down).

#### Figure Explanation:
An image is provided showing a bar of length \( 0.62 \, \text{m} \) inclined at \( 21^\circ \) to the vertical on the left side (end \( A \)) and \( 101^\circ \) to the horizontal on the right side (end \( B \)). End \( B \) has: 
- A velocity \( v_B = 0.58 \, \text{m/s} \) directed horizontally to the left.
- An acceleration \( a_B = 0.37 \, \text{m/s}^2 \) directed vertically downward.

#### Calculations:
Students are required to determine:
1. The angular acceleration \( \alpha \) of the bar.
2. The acceleration \( a_A \) of the end \( A \).

#### Input Fields:
- **Angular acceleration (\(\alpha\)):**  
  [Input Box] ``\(\displaystyle \text{rad/s}^2\)``
- **Acceleration of \( A \) (\(a_A\)):**  
  [Input Box] ``\(\displaystyle \text{m/s}^2\)``

#### Answers:
To solve this problem, use the rotational motion equations and kinematic relationships between the ends of the bar. The following steps can guide the calculations:

1. **Determine Angular Acceleration \( \alpha \):**
    - Use the relationship between the linear acceleration of end \( B \) and angular acceleration. 
    - Apply the geometric constraints provided by the angles.

2. **Acceleration of End \( A \) (\(a_A\)):**
    - Calculate based on the angular acceleration and the known conditions at end \( B \).

Students should apply the principles of rigid body dynamics to derive the equations for \( \alpha \)
Transcribed Image Text:### Angular and Linear Acceleration in a Rotating Bar #### Problem Statement: The ends of the 0.62-m bar remain in contact with their respective support surfaces. End \( B \) has a velocity of \( 0.58 \, \text{m/s} \) and an acceleration of \( 0.37 \, \text{m/s}^2 \) in the directions shown. Determine the angular acceleration \( \alpha \) (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end \( A \) (positive if up, negative if down). #### Figure Explanation: An image is provided showing a bar of length \( 0.62 \, \text{m} \) inclined at \( 21^\circ \) to the vertical on the left side (end \( A \)) and \( 101^\circ \) to the horizontal on the right side (end \( B \)). End \( B \) has: - A velocity \( v_B = 0.58 \, \text{m/s} \) directed horizontally to the left. - An acceleration \( a_B = 0.37 \, \text{m/s}^2 \) directed vertically downward. #### Calculations: Students are required to determine: 1. The angular acceleration \( \alpha \) of the bar. 2. The acceleration \( a_A \) of the end \( A \). #### Input Fields: - **Angular acceleration (\(\alpha\)):** [Input Box] ``\(\displaystyle \text{rad/s}^2\)`` - **Acceleration of \( A \) (\(a_A\)):** [Input Box] ``\(\displaystyle \text{m/s}^2\)`` #### Answers: To solve this problem, use the rotational motion equations and kinematic relationships between the ends of the bar. The following steps can guide the calculations: 1. **Determine Angular Acceleration \( \alpha \):** - Use the relationship between the linear acceleration of end \( B \) and angular acceleration. - Apply the geometric constraints provided by the angles. 2. **Acceleration of End \( A \) (\(a_A\)):** - Calculate based on the angular acceleration and the known conditions at end \( B \). Students should apply the principles of rigid body dynamics to derive the equations for \( \alpha \)
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