The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down).

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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X Incorrect
The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an
acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if
clockwise) of the bar and the acceleration of end A (positive if up, negative if down).
A
21°
101°
Answers:
a =
aA =
i
0.62 m
Bag=0.37 m/s²
2.2045
1.1279
UB=0.58 m/s
rad/s²
m/s²
Transcribed Image Text:X Incorrect The ends of the 0.62-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.58 m/s and an acceleration of 0.37 m/s² in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down). A 21° 101° Answers: a = aA = i 0.62 m Bag=0.37 m/s² 2.2045 1.1279 UB=0.58 m/s rad/s² m/s²
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