Calculate the Resultant Condition of the PIN in the drawing below: 1.000 O 1.060 0.982 O.995 0.008 C 2.000 Ø.995-1.000 +0.008MABC 6.00 None of these answers is correct X 3.000 Y 01.005-1.030 +0.005MABC B A .XX = .01 ANGLES = ± 1°
Calculate the Resultant Condition of the PIN in the drawing below: 1.000 O 1.060 0.982 O.995 0.008 C 2.000 Ø.995-1.000 +0.008MABC 6.00 None of these answers is correct X 3.000 Y 01.005-1.030 +0.005MABC B A .XX = .01 ANGLES = ± 1°
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:**Calculate the Resultant Condition of the PIN in the drawing below:**
The diagram shows a rectangular block with two circular pins drawn in the top view. Below the top view, a side view is presented.
- **Dimension Details:**
- The left pin has a diameter tolerance between 0.995 and 1.000.
- The right pin has a diameter tolerance between 1.005 and 1.030.
- The distance between the centers of the two pins is divided into segments of 2.000 and 3.000, totaling 6.000.
- The height from the top to the bottom in the front view is 1.000.
- **Tolerance Notes:**
- The left pin has a geometric tolerance of 0.008 with a maximum material condition (MMC) and datum references A, B, and C.
- The right pin has a geometric tolerance of 0.005 with MMC and datum references A, B, and C.
- The lower section of the diagram provides the general tolerance information:
- .XX precision = ±0.01
- Angle precision = ±1 degree
**Question Options:**
- ○ 1.060
- ○ .982
- ○ .995
- ○ .008
- ○ None of these answers is correct
The educational content aims to prompt the user to calculate the resulting condition of the pin based on the provided tolerances and dimensions.
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