**Calculate the Resultant Condition of the PIN in the drawing below:**The diagram shows a rectangular block with two circular pins drawn in the top view. Below the top view, a side view is presented. - **Dimension Details:** - The left pin has a diameter tolerance between 0.995 and 1.000. - The right pin has a diameter tolerance between 1.005 and 1.030. - The distance between the centers of the two pins is divided into segments of 2.000 and 3.000, totaling 6.000. - The height from the top to the bottom in the front view is 1.000.- **Tolerance Notes:** - The left pin has a geometric tolerance of 0.008 with a maximum material condition (MMC) and datum references A, B, and C. - The right pin has a geometric tolerance of 0.005 with MMC and datum references A, B, and C. - The lower section of the diagram provides the general tolerance information: - .XX precision = ±0.01 - Angle precision = ±1 degree **Question Options:**- ○ 1.060- ○ .982- ○ .995- ○ .008- ○ None of these answers is correctThe educational content aims to prompt the user to calculate the resulting condition of the pin based on the provided tolerances and dimensions.

Given: For pin LMC = 0.995 Geometric tolerance = 0.008 Bonus = MMC - LMC = 1.000-0.995 = 0.005

Calculate the Resultant Condition of the PIN in the drawing below: 1.000 O 1.060 0.982 O.995 0.008 C 2.000 Ø.995-1.000 +0.008MABC 6.00 None of these answers is correct X 3.000 Y 01.005-1.030 +0.005MABC B A .XX = .01 ANGLES = ± 1°

Calculate the Resultant Condition of the PIN in the drawing below: 1.000 O 1.060 0.982 O.995 0.008 C 2.000 Ø.995-1.000 +0.008MABC 6.00 None of these answers is correct X 3.000 Y 01.005-1.030 +0.005MABC B A .XX = .01 ANGLES = ± 1°

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Free Body Diagram

The system of forces acting on a body tends to either rotate it or make the body undergo motion. In general, when an external agent exerts a force on a body, the body undergoes translational motion and rotational motion. The body has six degrees of freedom under the influence of that force. Here, three degrees of freedom are from the translational motion while the other three are from the rotation motion. However, sometimes the bodies are not allowed to undergo any motion and are fixed, under such conditions the body is said to be constrained.

Question

**Calculate the Resultant Condition of the PIN in the drawing below:**

The diagram shows a rectangular block with two circular pins drawn in the top view. Below the top view, a side view is presented.

- **Dimension Details:**
- The left pin has a diameter tolerance between 0.995 and 1.000.
- The right pin has a diameter tolerance between 1.005 and 1.030.
- The distance between the centers of the two pins is divided into segments of 2.000 and 3.000, totaling 6.000.
- The height from the top to the bottom in the front view is 1.000.

- **Tolerance Notes:**
- The left pin has a geometric tolerance of 0.008 with a maximum material condition (MMC) and datum references A, B, and C.
- The right pin has a geometric tolerance of 0.005 with MMC and datum references A, B, and C.

- The lower section of the diagram provides the general tolerance information:
- .XX precision = ±0.01
- Angle precision = ±1 degree

**Question Options:**

- ○ 1.060
- ○ .982
- ○ .995
- ○ .008
- ○ None of these answers is correct

The educational content aims to prompt the user to calculate the resulting condition of the pin based on the provided tolerances and dimensions.

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