Wight Deflection 5 N High=10in 10 3.5 20 7 Width=1 in 40 16 20 9.9 10 Depth=5in 5 4 Calculation: Consider a block of rubber of length (L), height (h) and thickness(t). If a force (F) is applied downwards at a the supper surface of the slab will be deflected by (d). Area under shear stress L.t (m) Shear stress F/L.t (N/m) When force F(N)-mass(Kg)*acceleration (m/sec) Neglecting any displacement due to bending which is very small the whole of the displacement due to shearing. The shear strain is equal to the angle expressed in radians. Please write detailed The solution because e is small tan Modulus of Rigidity =G shear stress shear strain Led Not the modulus of rigidity is some times expressed as G or N Fill in the table Mass on Deformation Force(N) Shear Shear Modulus of Hanger M (Kg) Rigidity d (mm) stress strain

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Wight Deflection
5 N
High=10in
10
3.5
20
7
Width=1 in
40
16
20
9.9
10
6
Depth=5in
4
Calculation:
Consider a block of rubber of length (L), height (h) and thickness(t).
If a force (F) is applied downwards at a the supper surface of the slab will be deflected by (d).
Area under shear stress = Lt (m)
Shear stress = F/L.t (N/m)
When force F(N)Fmass(Kg)*acceleration (m /sec)
Neglecting any displacement due to bending which is very small the whole of the
displacement due to shearing. The shear strain is equal to the angle expressed in radians.
Please write detailed The
solution
tan =
because e is small
tan =
Modulus of Rigidity =G
shear stress
G
shear strain
Lt-d
Not the modulus of rigidity is some times expressed as G or N
Fill in the table
Mass on
Hanger M
(Kg)
Force(N)
Deformation
d (mm)
Modulus of
Rigidity
Shear
Shear
stress
strain
Transcribed Image Text:Wight Deflection 5 N High=10in 10 3.5 20 7 Width=1 in 40 16 20 9.9 10 6 Depth=5in 4 Calculation: Consider a block of rubber of length (L), height (h) and thickness(t). If a force (F) is applied downwards at a the supper surface of the slab will be deflected by (d). Area under shear stress = Lt (m) Shear stress = F/L.t (N/m) When force F(N)Fmass(Kg)*acceleration (m /sec) Neglecting any displacement due to bending which is very small the whole of the displacement due to shearing. The shear strain is equal to the angle expressed in radians. Please write detailed The solution tan = because e is small tan = Modulus of Rigidity =G shear stress G shear strain Lt-d Not the modulus of rigidity is some times expressed as G or N Fill in the table Mass on Hanger M (Kg) Force(N) Deformation d (mm) Modulus of Rigidity Shear Shear stress strain
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