A wood beam supports the loads shown. The cross-sectional dimensions of the beam are shown in the second figure. Assume LAB = 3.7 m, Lec= 1 m, Lcp = 1.8 m, w = 12.1 kN/m, P = 14.5 kN, b₁ = 10 mm, b₂ = 95 mm, d₁ = 100 mm, and d₂ = 240 mm. Determine the magnitude of: (a) the maximum horizontal shear stress Tmax in the beam. (b) the maximum tension bending stress max (and location x) in the beam.
A wood beam supports the loads shown. The cross-sectional dimensions of the beam are shown in the second figure. Assume LAB = 3.7 m, Lec= 1 m, Lcp = 1.8 m, w = 12.1 kN/m, P = 14.5 kN, b₁ = 10 mm, b₂ = 95 mm, d₁ = 100 mm, and d₂ = 240 mm. Determine the magnitude of: (a) the maximum horizontal shear stress Tmax in the beam. (b) the maximum tension bending stress max (and location x) in the beam.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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
Transcribed Image Text:**Wood Beam Analysis**
A wood beam supports the loads shown in the diagram. The cross-sectional dimensions of the beam are depicted in the second figure. Here are the given parameters for the analysis:
- **L\_AB** = 3.7 m
- **L\_BC** = 1 m
- **L\_CD** = 1.8 m
- **w** = 12.1 kN/m
- **P** = 14.5 kN
- **b1** = 10 mm
- **b2** = 95 mm
- **d1** = 100 mm
- **d2** = 240 mm
**Objective:**
Determine:
(a) The maximum horizontal shear stress (τ\_max) in the beam.
(b) The maximum tension bending stress (σ\_max) and its location (x) in the beam.
**Parameters to be calculated:**
- **τ\_max** (kPa)
- **σ\_max** (kPa)
- Location of **σ\_max** (x-coordinate in meters)
**Diagrams Explanation:**
1. **Beam Diagram:**
- The beam is supported at point A and has distributed loads labeled as "w" over section AB.
- A point load "P" is applied at the midpoint of section CD.
- The beam is divided into sections AB, BC, and CD with their respective lengths.
2. **Cross-sectional View:**
- Shows a rectangular beam section.
- Dimensions:
- **b1** (width of the top and bottom flanges) = 10 mm
- **b2** (width of the central web) = 95 mm
- **d1** (height of the central web) = 100 mm
- **d2** (overall height) = 240 mm
**Answers Section:**
- The maximum horizontal shear stress (τ\_max) in kPa is to be calculated.
- The maximum bending stress (σ\_max) in kPa and its location along the x-axis in meters are to be identified.
Expert Solution

Step 1: Determine the given Variables
Given
LAB=3.7 m
LBC=1 m
LCD=1.8 m
w=12.1 kN/m
P=14.5kN
b1=10 mm
b2=95 mm
d1=100 mm
d2=240 mm
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Solved in 6 steps with 7 images
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