What would be the major and minor product of (1E, 3E, 5E)-1-methoxyhepta-1,3,5-trien with the addition of HBr. Draw both products and explain why each product is either major or minor. *justify it*
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What would be the major and minor product of (1E, 3E, 5E)-1-methoxyhepta-1,3,5-trien with the addition of HBr. Draw both products and explain why each product is either major or minor. *justify it*
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- can you show me and outline the steps of solving thisDon't provide handwritten solutionMy question is about part C of the question shown. The answer is shown and then I drew an alternative with a red arrow. The question asks to draw a halogen that will ONLY form the alkene shown, not most of the time or sometimes, as many of our questions ask us to draw all the possible alkenese, even unlikely ones. This one has to be ONLY that one. My question is why the structure on the far right does NOT lead to a double bond between the two rings. There is a hydrogen on the opposite side of the Cl, isn't there? If there's not a hydrogen there, why not? What am I not seeing? Or if there is a hydrogen but that bond can't be made, why not?
- PayalbenDraw the major 1,2- and 1,4-addition products obtained in the reaction shown. Assume that both are derived from the most stable carbocation intermediate. +. HBr You do not have to consider stereochemistry. •You do not have to explicitly draw H atoms. If the 1,2- and 1,4- addition products are the same due to symmetry, only draw one structure. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate multiple products using the - sign from the drop-down menu. C. opy a3te, P.1, part A) In the reaction below, draw all of the possible products. 1, part B) For all the products you have drawn, draw their corresponding carbocations while also identifying if each is 1o/2o/3o carbocation. In addition, starting from alkene - provide complete accurate arrow-pushing mechanisms of each carbocation formation. 1, part C) In part B, circle the carbocation which is *most* stable, indicate why.
- Please answer with All the required steps needed to solve itCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the product of this elementary step in an SN1 mechanism. + Include all lone pairs and charges as appropriate. Ignore stereochemistry. Ignore byproducts. Nal <6) Write the mechanism (two propagation steps only, starting with the bromine radical in the first step and using Br2 in the second step) and that would explain how the following two products are produced. (Hint – the allylic radical is resonance stabilized.) Br Br NBS
- Highlight the electrophilic carbon in red, and highlight the leaving group in blue. Highlight the atom in the nucleophile that will attack the electrophilic center in green. Only atoms need to be highlighted and not the lone pairs or formal charges4. Which stereoisomer is the major product for the following reaction? Fill in the missing brackets with the key intermediate/transition state that leads to the preferred stereoisomer. Briefly explain (one sentence or bullet point) your selection. Br₂ key intermediate Br Br Br && or BrFor the dehydration shown, use curved arrows to show the formation of the carbocation intermediate in the presence of sulfuric acid H2SO4H2SO4, then draw the structures of the minor and major products of the elimination.