draw the complete mechanism for this double E2 elimination reaction?Starting Material: (2R,3S)-2,3-dibromo-3-phenylpropanoic acidFinal Product: Phenylpropiolic acidSteps to Include:Deprotonation of the carboxylic acid group: Show how the carboxylic acid (-COOH) group is deprotonated by KOH to form the carboxylate salt (-COO⁻).First E2 elimination: Illustrate the elimination of the first HBr molecule, forming the alkene intermediate.Second E2 elimination: Show the elimination of the second HBr molecule, forming the alkyne.Final protonation: Depict how HCl protonates the carboxylate group (-COO⁻) to regenerate the carboxylic acid (-COOH).Make sure to use proper arrow notation to show the movement of electrons in each step. Label all intermediates, reagents (KOH and HCl), and byproducts (HBr and KBr). I inldued some notes for how it kinda should look like IBr0+1-0конMethandон2. 1C), H₂OBr H✓↓ Acid-baseBB"

Answered: Image /qna-images/answer/e79a72f3-61ca-4c86-ac30-aaa28ef991ad.jpg

Answered: I Br 0 +1-0 кон Methand он 2. 1C), H₂O…

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 14.74QE: Lead poisoning has been a hazard for centuries. Some scholars believe that the decline of the Roman...

See similar textbooks

Related questions

Question

draw the complete mechanism for this double E2 elimination reaction?

Starting Material: (2R,3S)-2,3-dibromo-3-phenylpropanoic acid
Final Product: Phenylpropiolic acid
Steps to Include:
1. Deprotonation of the carboxylic acid group: Show how the carboxylic acid (-COOH) group is deprotonated by KOH to form the carboxylate salt (-COO⁻).
2. First E2 elimination: Illustrate the elimination of the first HBr molecule, forming the alkene intermediate.
3. Second E2 elimination: Show the elimination of the second HBr molecule, forming the alkyne.
4. Final protonation: Depict how HCl protonates the carboxylate group (-COO⁻) to regenerate the carboxylic acid (-COOH).

Make sure to use proper arrow notation to show the movement of electrons in each step. Label all intermediates, reagents (KOH and HCl), and byproducts (HBr and KBr). I inldued some notes for how it kinda should look like

I
Br
0
+1-0
кон
Methand
он
2. 1C), H₂O
Br H
✓
↓ Acid-base
B
B
"

Definition Definition Class of organic compounds that contain a carboxyl group ( - COOH ) and has a general formula R - COOH or R - CO 2 H , where R refers to the alkyl, alkenyl, aryl, or other groups. They can undergo different chemical reactions, such as acid-base reactions, esterification, and oxidation. These are essential components of living organisms, playing important roles in metabolic processes, signaling, and as pharmaceuticals.

Expert Solution