Add any remaining curved arrow(s) to complete step 1 of the mechanism, and modify the given drawing as needed to show the intermediate that is formed in this step. Use the single bond tool to interconvert between double and single bonds. ง H₂C CH3 CH3 CH3 H₂C. CH₂

The Wolff–Kishner reaction uses hydrazine (H2NNH2) and hydroxide (–OH) to reduce a carbonyl to the alkane. The first steps of the mechanism convert a carbonyl to a hydrazone in a manner similar to imine formation. Draw the mechanism arrows for the reaction from the hydrazone to the alkane. Be sure to add lone pairs of electrons and nonzero formal charges to all species.

The reactants, intermediates, final products, and all curved arrows showing bonds forming andbreaking are collectively referred to as the mechanism of a reaction. For the following reactants: a. Explain why the original statement of Markovnikov’s rule does not help in this case, but themodern restatement of Markovnikov’s rule tells you which carbon will get the X (Cl). b. Show the mechanism of the most likely addition reaction between the reactants.

Draw the curved-arrow mechanism with the drawings of the molecules, not just abbreviations. -NO₂ Sn, HCl (aq) E D H (CH3CO)₂O -NH2 CH3

Draw a mechanism for this reaction. H₂C- CH3 -0- Interactive 3D display mode -CH3 H₂C CH₁₂ H₂C-O i Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be created.

In the presence of light or heat, diazomethane (CH,N2) creates a carbene, which then adds to an alkene to make a cyclopropane. In the boxes below. draw the mechanism arrows for the reaction. H INEN: INE N:

Please explain mechanism step by step. Thanks!!

On a scrap piece of paper, draw the curved arrow mechanism for the following reaction. Once you have determined the major product, draw it in the space below. 1) PhLi 2) H₂O 8 [In TI H C ZO N 0 S Marvin JS by ChemAxon LL F P CI ଏ Br

Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. LOCH3 LOCH3 HNO3 / CH3CO₂H O₂N • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. ● In cases where there is more than one answer, just draw one.

The reaction of 1-bromobutane with sodium hydroxide affords the substitution product butan-1-ol. What would happen to the rate of the reaction if the concentration of both 1-bromobutane and sodium hydroxide were doubled? The rate increases by a factor of 4. The rate decreases by a factor of 2. The rate remains the same. The rate increases by a factor of 2.