Solution (1): 0.15 M CH2(CO2H)2 and 0.020 M MnSO4 0.15M 0.020M This solution has two solutes: malonic acid, CH2(CO₂H)2, and manganese(II) sulfate, MnSO4. Both of these compounds exist as solids at room temperature. Therefore solution (1) is of the solid-in- liquid type. Figure 1 outlines the general procedure for preparing this type of solution. 1. Weigh each solid solute to obtain desired amounts. Roll or fold into a funnel. 4. Continue to add water until water level reaches the etched mark on the neck of the volumetric flask. 2. Transfer solids from weighing paper into a volumetric flask. 3. Add distilled water to partially filled the flask; swirl to dissolve the solids. Figure 1. Procedure for Preparing Solid-in-Liquid Solutions 1. On your report sheet, calculate the amount of each solute needed (questions 1 and 2) to prepare 50.0 mL of solution (1). NOTE: your answers should include appropriate units and the correct number of significant figures.
Solution (1): 0.15 M CH2(CO2H)2 and 0.020 M MnSO4 0.15M 0.020M This solution has two solutes: malonic acid, CH2(CO₂H)2, and manganese(II) sulfate, MnSO4. Both of these compounds exist as solids at room temperature. Therefore solution (1) is of the solid-in- liquid type. Figure 1 outlines the general procedure for preparing this type of solution. 1. Weigh each solid solute to obtain desired amounts. Roll or fold into a funnel. 4. Continue to add water until water level reaches the etched mark on the neck of the volumetric flask. 2. Transfer solids from weighing paper into a volumetric flask. 3. Add distilled water to partially filled the flask; swirl to dissolve the solids. Figure 1. Procedure for Preparing Solid-in-Liquid Solutions 1. On your report sheet, calculate the amount of each solute needed (questions 1 and 2) to prepare 50.0 mL of solution (1). NOTE: your answers should include appropriate units and the correct number of significant figures.
General, Organic, and Biological Chemistry
7th Edition
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:H. Stephen Stoker
Chapter8: Solutions
Section: Chapter Questions
Problem 8.10EP: A solution is made by dissolving 0.455 g of PbBr2 in 100 g of H2O at 50C. Based on the data in Table...
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