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- (b) 1.9-BBN 2. H₂O2, KOHstudent found a bottle of unknown origin in the basement of an "CAUTION—contains С₁H₁O.” No other A old house. The bottle was labelled information was given, but inside the bottle were some white crystals. The student took the bottle to a chemistry laboratory, where she analyzed the crystals with the help of the laboratory staff. C₁2H₁6O reacted with Br₂ in CCl4 adding one mole of Br, and forming C₁₂H₁OB2₂. When a sample of C₁₂H₂O was reacted with O3 followed by Zn/H₂O, two different samples, J and K, were obtained. Compound J had a molecular formula of C.HgO₂, and its NMR is shown below. Compound K had a molecular formula of C₂H₂O, and it could be oxidized to compound L, with a molecular formula of C₂H₂O₂. The IR spectrum of L showed a very wide, strong band centred around 3000 cm*¹. The NMR spectrum of L showed only two different absorptions: a doublet (6H) at 0.9 ppm and a septet (1H) at 3.6 ppm. There was also a singlet (1H) off the scale at 11.8 ppm. students, deduce possible…1. 2. OCH3 + 1. NaOEt 2. CH₂CH₂Cl 3. NaOEt 4. CH₂Br 1. LiAlH, OCH3 NaOCH3 H₂O
- Q5. As part of the aspirin synthesis lab, the orgo students also had to perform the following calculation to demonstrate their knowledge. Are you able to help them work this out? Saponification is a process in which soap is produced from the chemical reaction between animal fat (triglycerides) and a strong base such as KOH. An example of such a balanced chemical reaction is shown here: C51H98O6 + 3KOH à C3H5(OH)3 + 3C16H31O2K Triglyceride Soap If, during the saponification reaction, 231.5 g of C51H98O6 is mixed with 231.5 g of KOH and 160 g of soap is produced: Calculate the theoretical yield of soap (in grams), C16H31O2K, and indicate which species is the limiting reactant. Provide your answer to 2 decimal places (5). Calculate the percent yield for this reaction. Provide your answer to 1 decimal place (1). Show ALL steps and equations involved in your calculations. Remember to label all steps clearly and use appropriate units.1. HNO3, H₂SO4 2. PCC 3. Na₂Cr₂O7, H₂SO4 4. Br₂, FeBr3 5. PBr3 6. H₂C=0 7. 1. LIAIH4 2. H3O*, H₂O 8. HBr 9. H₂O, H* 10. CH3CH₂CH₂CI, AICI3 11. CH3CH₂CH=PPh3 12. Zn-Hg, EtOH, HCI 13. Li, THF 14. 1. CH₂CH₂CH₂MgCl 2. H₂O, H* 15. KMnO4 16. HOCH₂CH₂OH, H₂O* 17. CH3CH₂OH, H* 20. 1. BHs 2. HzOz, NaOH 21. CH3CH₂CH₂Br 18. 1. 2 CH3Li 2. HyO*, H,O 19. 1. CH,CH,CH,Li 2. HyO*, H2O2.97 LDPE has a density in the range of 0.915—0.935 g/cm3, and HDPF has a density in the range of 0.940—0.965 g/cm3. You receive a small disk, 2.0 cm high with a 6.0-cm diameter, from a manufacturer of polyethylene, but its label is missing. You measure the mass of the disk and find that it is 53.8 g. Is the material HDPE or LDPE?
