Macmillan Learning A 0.4400 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO2 · 4 H₂O and removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 15.00 mL aliquot of this solution was buffered, and titration of the lead, copper, and zinc in solution required 35.84 mL of 0.001532 M EDTA. Thiosulfate was used to mask the copper in a second 20.00 mL aliquot. Titration of the lead and zinc in this aliquot required 34.09 mL of the 0.001532 M EDTA solution. Finally, cyanide was used to mask the copper and the zinc in a third 25.00 mL aliquot. Titration of the lead in this aliquot required 25.01 mL of the 0.001532 M EDTA solution. Determine the percent composition by mass of each metal in the pewter sample.

Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter18: Representative Metals, Metalloids, And Nonmetals
Section: Chapter Questions
Problem 25E: A chemist dissolves a 1.497-g sample of a type of metal (an alloy of Sn, Pb, Sb, and Cu) in nitric...
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Macmillan Learning
A 0.4400 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO2 · 4 H₂O
and removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 15.00 mL aliquot of
this solution was buffered, and titration of the lead, copper, and zinc in solution required 35.84 mL of 0.001532 M EDTA.
Thiosulfate was used to mask the copper in a second 20.00 mL aliquot. Titration of the lead and zinc in this aliquot required
34.09 mL of the 0.001532 M EDTA solution. Finally, cyanide was used to mask the copper and the zinc in a third 25.00 mL
aliquot. Titration of the lead in this aliquot required 25.01 mL of the 0.001532 M EDTA solution. Determine the percent
composition by mass of each metal in the pewter sample.
Transcribed Image Text:Macmillan Learning A 0.4400 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO2 · 4 H₂O and removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 15.00 mL aliquot of this solution was buffered, and titration of the lead, copper, and zinc in solution required 35.84 mL of 0.001532 M EDTA. Thiosulfate was used to mask the copper in a second 20.00 mL aliquot. Titration of the lead and zinc in this aliquot required 34.09 mL of the 0.001532 M EDTA solution. Finally, cyanide was used to mask the copper and the zinc in a third 25.00 mL aliquot. Titration of the lead in this aliquot required 25.01 mL of the 0.001532 M EDTA solution. Determine the percent composition by mass of each metal in the pewter sample.
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