6.22 Consider the following mechanism for formation of a double helix from its strands A and B: A+ Bunstable helix (fast) unstable helix → stable double helix (slow) Derive the rate equation for the formation of the double helix and express the rate constant of the reaction in terms of the rate constants of the individual steps. What would be your conclusion if the pre-equilibrium assumption was replaced by the steady-state approximation?
6.22 Consider the following mechanism for formation of a double helix from its strands A and B: A+ Bunstable helix (fast) unstable helix → stable double helix (slow) Derive the rate equation for the formation of the double helix and express the rate constant of the reaction in terms of the rate constants of the individual steps. What would be your conclusion if the pre-equilibrium assumption was replaced by the steady-state approximation?
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter13: Chemical Kinetics
Section: Chapter Questions
Problem 13.3QE: What is the difference between the integrated and differential forms of the rate law?
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Question
6.22: In addition to solving the problem please give brief explanation for concepts and solution if able.

Transcribed Image Text:6.22 Consider the following mechanism for formation of a
double helix from its strands A and B:
A+ Bunstable helix (fast)
unstable helix → stable double helix (slow)
Derive the rate equation for the formation of the double helix
and express the rate constant of the reaction in terms of the
rate constants of the individual steps. What would be your
conclusion if the pre-equilibrium assumption was replaced by
the steady-state approximation?
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