Suppose the formation of tert-butanol proceeds by the following mechanism: step elementary reaction rate constant (CH), СBr (aq) —(CH),С (aq) + Br (aq) c* 1 2 | (CH), С"(аq) + он (аа) — (СH;), СоН(а) (CH3), COH(aq) Suppose also k,«k,. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction: Write the experimentally- observable rate law for the overall chemical reaction. rate = k Note: your answer should not contain the concentrations of any intermediates.
Catalysis and Enzymatic Reactions
Catalysis is the kind of chemical reaction in which the rate (speed) of a reaction is enhanced by the catalyst which is not consumed during the process of reaction and afterward it is removed when the catalyst is not used to make up the impurity in the product. The enzymatic reaction is the reaction that is catalyzed via enzymes.
Lock And Key Model
The lock-and-key model is used to describe the catalytic enzyme activity, based on the interaction between enzyme and substrate. This model considers the lock as an enzyme and the key as a substrate to explain this model. The concept of how a unique distinct key only can have the access to open a particular lock resembles how the specific substrate can only fit into the particular active site of the enzyme. This is significant in understanding the intermolecular interaction between proteins and plays a vital role in drug interaction.
![Suppose the formation of tert-butanol proceeds by the following mechanism:
step
elementary reaction
rate constant
CBr(aq)
(CH), С"(аg) + Br (ag)
c*
k
1
2 (CH3),C"(aq) + OH (aq) → (CH,),COH(aq)
k2
3
3
Suppose also k, «k,. That is, the first step is much slower than the second.
Write the balanced
chemical equation for the
overall chemical reaction:
Write the experimentally-
observable rate law for the
overall chemical reaction.
rate = k U
Note: your answer should
not contain the
concentrations of any
intermediates.
Express the rate constant
k for the overall chemical
reaction in terms of k1, k2,
and (if necessary) the rate
constants k.1 and k-2 for
0
k =
the reverse of the two
elementary reactions in
the mechanism.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F36e9e6bf-5fca-412d-926f-13eedac0d9c5%2F487e4348-5506-4a29-b095-09f43491a982%2Fl0iwien_processed.png&w=3840&q=75)
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