The overall reaction produced by the aldol condensation of acetophenone and benzaldehyde is shown below. + NaOH, A Acetophenone Benzaldehyde Chalcone Which of the following steps are involved in the mechanism that leads to the formation of chalcone? он + он H OH он + Он OH + Тон Он он + + Он ОН + он
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- Draw the structures A, B and C for the reaction sequence below.order the following carbonyl groups in terms of reactivity with nucleophiles (least reactive first) acetaldehyde formaldehyde acetone acetyl chloride acetic acidNaOH, H₂O, 5°C Identify the potential products of the aldol addition depicted below from the given compounds. он он О он Он О Он OH ОН ОН
- Rank the following carbonyl compounds in order of increasing reactivity towards nucleophilesDraw the structures of the two Aldol condensation products based on the identified aldehydes and ketones.The Robinson annulation involves two sequential reactions, a Michael addition and an aldol condensation, resulting in the formation of a cyclohexenone derivative. Draw the structure of the two neutral reactants required to form the product shown below. NAOCH, CH,0H
- Complete the following reaction by mechanism E1 and E2. Present all steps and all possible products in each mechanism. See the image.Please draw all structures (show the CO2Et structure) and label it clearly. Thank you!The Stork reaction is a condensation reaction between an enamine donor and an α,β-unsaturated carbonyl acceptor. The overall reaction consists of a three-step sequence of formation of an enamine from a ketone, Michael addition to an α,β-unsaturated carbonyl compound, and hydrolysis of the enamine in dilute acid to regenerate the ketone. Consider the Stork reaction between cyclohexanone and propenal Draw the structure of the product of the enamine formed between cyclohexanone and dimethylamine. - Michael addition to an α,β-unsaturated carbonyl compound, and - hydrolysis of the enamine in dilute acid to regenerate the ketone.
- Alkyl diazonium salts are unstable even at low temperature. They decompose to form carbocations, which go on to form products of substitution, elimination, and (sometimes) rearrangement. Keeping this in mind, draw a stepwise mechanism that forms all of the following products. NANO2 он + HCI, H2O NH2 онDraw the major product of the following reaction sequence. OH H2CrO4 HO NaBH4 H*/H20 ELOH он H3C* ноRank the following reactions in order of increasing nucleophile strength: Cl-, H2O, CH3-, H2S, HS-, I-