The equilibrium constant in terms of pressures, Kp, for the reaction NH3(g) + HF(g) NH4F(s) at 25 °C is 10.2. (a) If the partial pressure of ammonia is P NH3 = 0.893 atm and solid ammonium fluoride is present, what is the equilibrium partial pressure of hydrogen fluoride at 25 °C? P = HF atm (b) An excess of solid NHF is added to a container filled with NH3 at 25 °C and a pressure of 1.04 atm. Calculate the pressures of NH3(g) and HF(g) reached at equilibrium. P atm NH3 P = HF atm

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter12: Gaseous Chemical Equilibrium
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The equilibrium constant in terms of pressures, Kp, for the reaction
NH3(g) + HF(g)
NH4F(s)
at 25 °C is 10.2.
(a) If the partial pressure of ammonia is P
NH3
= 0.893 atm and solid ammonium fluoride is present, what is the equilibrium partial pressure of hydrogen fluoride at 25 °C?
P =
HF
atm
(b) An excess of solid NHF is added to a container filled with NH3 at 25 °C and a pressure of 1.04 atm. Calculate the pressures of NH3(g) and HF(g) reached at equilibrium.
P
atm
NH3
P
=
HF
atm
Transcribed Image Text:The equilibrium constant in terms of pressures, Kp, for the reaction NH3(g) + HF(g) NH4F(s) at 25 °C is 10.2. (a) If the partial pressure of ammonia is P NH3 = 0.893 atm and solid ammonium fluoride is present, what is the equilibrium partial pressure of hydrogen fluoride at 25 °C? P = HF atm (b) An excess of solid NHF is added to a container filled with NH3 at 25 °C and a pressure of 1.04 atm. Calculate the pressures of NH3(g) and HF(g) reached at equilibrium. P atm NH3 P = HF atm
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