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- 1:39 1 Send a chat Be sure to answer all parts. Nitroglycerin (C;H;N3O9) is a powerful explosive. Its decomposition may be represented by 4C3H3N3O9 → 6N2 + 12CO, + 10H20 + O2 This reaction generates a large amount of heat and gaseous products. It is the sudden formation of these gases, together with their rapid expansion, that produces the explosion. ok (a) What is the maximum amount of O, in grams that can be obtained from 7.50 × 10² g of nt nitroglycerin? g ences (b) Calculate the percent yield in this reaction if the amount of O, generated is found to be 24.5 %nHMAC%3Def41415d9158412623399163083b2ede#10001 Spr. 2021 8 Gu HI, Leira v Sign Out Item 4 I Review | Constants | Periodic Table Alexandra decides to climb Mt. Krumpett, which is 5000 m high. She determines that this will require a total of 2250 kcal of energy for the trip. For her food supply, she decides to take nutrition bars. The label states that each bar contains 50 g of carbohydrates, 10 g of fat, and 40 g of protein. Part A How many nutrition bars should Alexandra pack? Express the number of bars numerically. > View Available Hint(s) ν ΑΣφ bars Submit Previous Answers 0V 12:33? 1. 03-78°C 2. (CH3)₂S + byl H i H H
- 1-61 The density of dichloromethane, a liquid insoluble in water, is 1.33 g/cc. If dichioromethane and water are placed in a separatory funnel, which will be the upper layer?1-86 The specific heats of some elements at 25oC are as follows: aluminum = 0.215 cal/g · oC; carbon (graphite) = 0.170 caI/g oC; iron = 0.107 cal/g mercury = 0.033 1 caI/g oC. (a) Which element would require the smallest amount of heat to raise the temperature of 100 g of the element by 10oC? (b) If the same amount of heat needed to raise the temperature of 1 g of aluminum by 25oC were applied to 1 g of mercury, by how many degrees would its temperature be raised? (c) If a certain amount of heat is used to raise the temperature of 1.6 g of iron by 10oC, the temperature of 1 g of which element would also be raised by 10oC, using the same amount of heat?Conyugated acid Conyugated bese Jamula ha Formula ha A NH 5.61010 CH,NH HCO 2.2 10-8 Complete the table below. B Sure cach OA Your cinowrentries has the Correct numbCr oA Signiticant digits. You may assime the tamparature is 25°C.
- (Al,(S0.);) A chemist must dilute 20.6 mL of 22.0 mM aqueous aluminum sulfate solution until the concentration falls to 9.00 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Be sure your answer has the correct number of significant digits. ||mLHNO3 d= H* Br f.CH₂-COOH Citric acid has the formula HO-C-COOH I CH₂-COOH CH2–CDD - Na* + HD-C-CDD- Na CH₂-COO- COO-Na A 25.0 mL sample of a concentrated citrus fruit cordial component (e.g. for lime juice), used in the food & drinks industry, was diluted to 250 mL in a graduated volumetric flask. A 25.0 mL sample of this diluted solution, required, on average, 22.5 mL of a standard 0.100 molar sodium hydroxide solution using phenolphthalein indicator for the titration end-point. A) 0.0075 Assuming all the acid in the cordial was citric acid, calculate the concentration of the acid in g/mL in the original solution. B) 0.576 D and is tribasic acid, forming the tri-sodium salt on complete neutralisation with sodium hydroxide. 1.44 0.00225
- (1) Br2 CC,a .ull Asiacel| 10 N 141 N O A box with a volume (V=0.05 m³) lies at the bottom of a lake whose water has a density of (1*10³ kg/m³). How much force is required to lift the box, .if the mass of the box is (1000 kg) 9319.5 N O 9313.9 N O 9391.5 N O 9315.9 N O A future rectangular ship filled with oil. If the dimensions of the ship are (250 m) long, (80 m) wide, and (80 m) high. Determine how far the bottom of the ship is below the sea level? (Consider the total mass of the ship with the oil is (10.2*108 kg), and the .sea density is (1024 kg/m³))I don’t understand these two questions.(66 and 67)
