4. The equilibrium constant for the dissociation of hydrogen sulfide (H2S) to bisulfide ion (HS-) at 25 °C is 10-7.02. Calculate the equilibrium constant for this reaction from 0°C to 30ºC in 5ºC increments and plot log K vs. T. Does dissociation of H2S become more or less favorable as temperature increases?

Chemistry: The Molecular Science
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Author:John W. Moore, Conrad L. Stanitski
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Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
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4. The equilibrium constant for the dissociation of hydrogen sulfide (H2S) to bisulfide ion (HS-)
at 25 °C is 10-7.02. Calculate the equilibrium constant for this reaction from 0°C to 30ºC in
5ºC increments and plot log K vs. T. Does dissociation of H2S become more or less favorable
as temperature increases?
Transcribed Image Text:4. The equilibrium constant for the dissociation of hydrogen sulfide (H2S) to bisulfide ion (HS-) at 25 °C is 10-7.02. Calculate the equilibrium constant for this reaction from 0°C to 30ºC in 5ºC increments and plot log K vs. T. Does dissociation of H2S become more or less favorable as temperature increases?
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