Part A: Draw the structure of cis-1-ethyl-2-methylcyclohexane. Part B: Using chair conformations, draw two conformational isomers, and determine which is more stable.
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Part B: Using chair conformations, draw two conformational isomers, and determine which is more stable."
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- In the drawing areas below, draw the two conformations of bromocyclohexane that are typically the most stable. Be sure your drawings make it possible to distinguish between the conformations. After you've drawn the conformations, answer the question below the drawing areas. G chair flip Click and drag to start drawing a structure. Of the two conformations you drew above, which is the more stable? O left O right ◇ they are equally stable cannot decide without more information X X Click and drag to start drawing a structure. CThe energy difference between a tert-butyl group going from equatorial to axial in a cyclohexane is 18.3 kJ/mol. When two of the carbon atoms are replaced with oxygen atoms (molecule B) the energy difference between the two chair conformations drops to 5.9 kJ/mol. Explain this difference. (Hint: Consider what makes putting groups axial unfavorable).It is easy to imagine a cyclohexane as a flat hexagon and a lot of the time we draw it that way. Looking at 1,3,5-triethylcyclohexane we cannot tell the stability of the molecule from looking at the flat 2D drawing. Explain why we need to look at the 3D configuration and what conformation (axial,equatorial) would each of the three ethyl groups be in for the most stable configuration.
- Draw a structural formula for cis-1-bromo-3-ethylcyclopentane. • Show stereochemistry only if given in the name. • In cases where there is more than one answer, just draw one.5. Draw the most stable conformation of 1,4-dichlorobutane using wedges and dashes to represent bonding coming out of the paper and going behind the paper, respectively. This should look like a zigzag. You can use a skeleton for the carbon backbone if you like.Hello, I was reading an answer from the book Organic Chemistry by Brown et al. The question is 2.51 "Draw alternative chair conformations for each substituted cyclohexane and state which chair is more stable." There are then 4 cyclohexanes (labeled a-d). For the "a" cyclohexane, the substituents are arranged as a combination of axial and equatorial in both chair conformations. However, for the "b," "c," and "d," cyclohexanes one chair has only equatorial substituents, and the other chair has only axial substituents. Why is the "a" chair conformation different? https://www.bartleby.com/solution-answer/chapter-2-problem-251p-organic-chemistry-8th-edition/9781305580350/draw-alternative-chair-conformations-for-each-substituted-cyclohexane-and-state-which-chair-is-more/4532cd91-c341-11e9-8385-02ee952b546e
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